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3 years ago

HHHHHHHHHHHEEEEEEEEEELLLLLLLLPPPPPPP FIRST RIGHT GITS BRAINLEST

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

300

Step-by-step explanation:

faltersainse [42]3 years ago

8 0

Answer:

Her answer is right give her brainliest

Step-by-step explanation:

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What is x? -2.5x- 2=18

snow_tiger [21]

Answer:

x = -8

Step-by-step explanation:

-2.5x - 2 = 18.

Add 2 to both sides.

-2.5x = 20.

Divide both sides by -2.5.

x = -8

3 0

3 years ago

Round 2,253 to hundred

Advocard [28]

Answer:

2300

Step-by-step explanation:

5 0

4 years ago

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PLS Help me! This graph shows the outside temperature (in degrees Celsius) over the course of 12 hours, starting at midnight (x

viktelen [127]

Answer:

The domain is the set of all possible x-values

Domain is the time here

The range is the resulting y-values

The range is the outside temperature is here

Function is decreasing between x= 0 to 3

It means the temperature is decreasing between midnight and 3 AM

5 0

3 years ago

The volume of a rectangular prism is 4800 cm3. The base is 12 cm long and 20 cm wide.

AnnZ [28]

Answer:

A. 20cm hope this helps

Step-by-step explanation:

7 0

3 years ago

(ASAP PICTURE ADDED) What is the simplified form of the following expression?

bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$

$(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)$

So, option c is correct

5 0

3 years ago

Read 2 more answers