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3 years ago

Determine the general solution of 2 sin x.cos x-cos x=0

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

${ \tt{(2 \sin x. \cos x) - \cos x = 0}} \\ \\{ \tt{ \cos x(2 \sin x - 1) = 0 }} \\ either : { \tt{ \cos x = 0 \: \: or \: \: (2 \sin x - 1) = 0}} \\ \\ { \boxed{ \bf{x = 30 \degree, \: 90 \degree, \: 150 \degree,\:270\degree}}}$

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balu736 [363]

Answer:

Option A. one rectangle and two triangles

Option E. one triangle and one trapezoid

Step-by-step explanation:

step 1

we know that

The area of the polygon can be decomposed into one rectangle and two triangles

see the attached figure N 1

therefore

Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles

$A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2$

step 2

we know that

The area of the polygon can be decomposed into one triangle and one trapezoid

see the attached figure N 2

therefore

Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid

$A=\frac{1}{2}(8)(4)+\frac{1}{2}((4+8)(8)=16+48=64\ yd^2$

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3 years ago

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KIM [24]

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3 years ago

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Mrrafil [7]

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3 years ago

Read 2 more answers

DOES THIS SET OF ORDERED PAIRS<br> REPRESENT A FUNCTION?<br> {(2,4),(2,5), (2,6), (2,7) }

vlabodo [156]

Answer:
No, this set of ordered pairs does not represent a function.

Explanation:
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kenny6666 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Determine the general solution of 2 sin x.cos x-cos x=0​

Determine the general solution of 2 sin x.cos x-cos x=0