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3 years ago

Determine the general solution of 2 sin x.cos x-cos x=0

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

${ \tt{(2 \sin x. \cos x) - \cos x = 0}} \\ \\{ \tt{ \cos x(2 \sin x - 1) = 0 }} \\ either : { \tt{ \cos x = 0 \: \: or \: \: (2 \sin x - 1) = 0}} \\ \\ { \boxed{ \bf{x = 30 \degree, \: 90 \degree, \: 150 \degree,\:270\degree}}}$

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3 years ago

How do you solve this?

frosja888 [35]

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3 years ago

On the following number line, two rational numbers are graphed.Represent the two numbers as fractions (or mixed numbers) in lowe

nordsb [41]

The first graphed rational number is at the middle of -2 and -1, thus the number represented is $-1 \frac{1}{2}$

The second graphed number is five out of six places from from 0 to 1, thus the number graphed is $0+ \frac{5}{6} = \frac{5}{6}$

The difference between the two numbers can be represented as
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or
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To find the difference,

$-1 \frac{1}{2} - \frac{5}{6} \\ \\ =-1 \frac{3+5}{6} \\ \\ =-1 \frac{8}{6} =-2 \frac{2}{6} \\ \\ =-2 \frac{1}{3}$

Also,

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4 years ago

A robot can complete 7 tasks in

SSSSS [86.1K]

Answer:

5/42 is your answer take robot to complete

7 tasks = 5/6

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3 years ago

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matrenka [14]

Answer:

Tj should write 5.75 hours on her time card.

Step-by-step explanation:

We have been given, Tj worked for 5 hours and 45 minutes.

We will convert 45 minutes to hours by dividing 45 by 60 as one hour has 60 minutes.

$\frac{45 minutes }{60} \times\frac{hour}{minutes}$

=0.75 hours

Hence, Tj should write 5.75 hours on her time card.

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3 years ago

Determine the general solution of 2 sin x.cos x-cos x=0​

Determine the general solution of 2 sin x.cos x-cos x=0