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GuDViN [60]
3 years ago
13

Determine the general solution of 2 sin x.cos x-cos x=0​

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

{ \tt{(2 \sin x. \cos x) -  \cos x = 0}} \\  \\{ \tt{ \cos x(2 \sin x - 1) = 0 }} \\ either : { \tt{ \cos x = 0 \:  \: or \:  \: (2 \sin x - 1) = 0}} \\  \\ { \boxed{ \bf{x = 30 \degree, \:  90 \degree,  \: 150 \degree,\:270\degree}}}

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Here's what I get  

Step-by-step explanation:

a) Possible degree

This  looks like the graph of a cubic equation.

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The leading coefficient must be positive.

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ƒ(x) is decreasing in the interval (-4, -1).

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