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3 years ago

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I NEED HELP DESPERATELY PLEASE! Which is NOT a good reason to establish a positive credit history? A) To be able to borrow money

for large purchases. B) To be able to get a certain job. C) To be able to borrow money at a lower interest rate. D) To guarantee that you will qualify for any credit card. Thank you!

1 answer:

JulijaS [17]3 years ago

4 0

Answer:

A

Step-by-step explanation:

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find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6

taurus [48]

Answer:

$f(x) = \frac{6}{x^2} -8$ or $f(x) = -\frac{6}{x^2} + 4$

Step-by-step explanation:

Given

$(x,y) = (1,-2)$ --- Point

$\int\limits^6_2 {(1 + 144x^{-6})} \, dx$

The arc length of a function on interval [a,b]: $\int\limits^b_a {(1 + f'(x^2))} \, dx$

By comparison:

$f'(x)^2 = 144x^{-6}$

$f'(x)^2 = \frac{144}{x^6}$

Take square root of both sides

$f'(x) =\± \sqrt{\frac{144}{x^6}}$

$f'(x) = \±\frac{12}{x^3}$

Split:

$f'(x) = \frac{12}{x^3}$ or $f'(x) = -\frac{12}{x^3}$

To solve fo f(x), we make use of:

$f(x) = \int {f'(x) } \, dx$

For: $f'(x) = \frac{12}{x^3}$

$f(x) = \int {\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = \frac{12}{2x^2} + c$

$f(x) = \frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = \frac{6}{1^2} + c$

$-2 = \frac{6}{1} + c$

$-2 = 6 + c$

Make c the subject

$c = -2-6$

$c = -8$

$f(x) = \frac{6}{x^2} + c$ becomes

$f(x) = \frac{6}{x^2} -8$

For: $f'(x) = -\frac{12}{x^3}$

$f(x) = \int {-\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = -\frac{12}{2x^2} + c$

$f(x) = -\frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = -\frac{6}{1^2} + c$

$-2 = -\frac{6}{1} + c$

$-2 = -6 + c$

Make c the subject

$c = -2+6$

$c = 4$

$f(x) = -\frac{6}{x^2} + c$ becomes

$f(x) = -\frac{6}{x^2} + 4$

3 0

3 years ago

Which algebraic representation describes the graphed dilation?

icang [17]

Please send the information
Please help us get to my place for the new
Please it back please send him to send your information and let him do
O I don’t know how to open it .
Just need point sorry I hate school

8 0

3 years ago

What is the value of the expression 4x y/2x-y when x=2 and y=4?

neonofarm [45]

This function is undefined. E side of you plug the values of x and y into the denominator the denominator = 0 and you cannot divide by zero

7 0

3 years ago

Write the following in interval notation:

elena-14-01-66 [18.8K]

Answer:

10/13 ≤ x < 18/13

Step-by-step explanation:

-1 ≤ 13x - 11 < 7

If a ≤ u < b then a ≤ u and u < b

⇒ -1 ≤ 13x - 11 and 13x - 11 < 7

-1 ≤ 13x - 11

Add 11 to both sides: 10 ≤ 13x

Divide both sides by 13: 10/13 ≤ x

13x - 11 < 7

Add 11 to both sides: 13x < 18

Divide both sides by 13: x < 18/13

Combine the intervals

10/13 ≤ x < 18/13

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3 years ago

Compute by using Unit Fractions.

blsea [12.9K]

Answer:

A or B i hope this helps! sorry

Step-by-step explanation:

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4 years ago