Step-by-step explanation:


Note that


Therefore,

Answer:
0.0537
Step-by-step explanation:
This follows a binomial distribution with : n
Number of trials 'N' = 12 ; Probability of success (difference between speakers) 'p' = 1/2 or 0.5 ; Probability of failure (no difference b/w speakers) = 1/2 or 0.5 ; No of success 'r' = 3
P (X = 3) = 
= 12C3 (0.5)^3 (0.5)^9
0.0537
Answer:
113.04cm²
Step-by-step explanation:
area of circle= π r²
Area= 6* 6*3.14=113.04 cm²
Answer:
149.28 sq. inches
137.5 cubic inches.
Step-by-step explanation:
The cylindrical container has length or height (h) 7 inches and has a diameter of 5 inches i.e. radius (r) 2.5 inches.
Now, total surface area of the container =
=
= 39.28 + 110
= 149.28 sq. inches (Answer)
Again the volume of the container will be
=
= 137.5 cubic inches. (Answer)
Answer:

Step-by-step explanation:
We are given the expression to be simplified:

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.
We know that:

Let us use it to solve the powers of 5 in the given expression.
we can write:


The given expression becomes:

Taking common
from the numerator and
Taking common
from the denominator

The answer is:
