Answer:
B) TS = -6.51, p-value = 0.0000
Step-by-step explanation:
Sample size, n = 39
μ = 7.5 cm
Null hypothesis, H₀ = 7.5 cm
(I.e. Average height of youngest child is 7.5 cm)
Alternative hypothesis, 
(The youngest child's age is underestimated by 7.5 cm)
Standard deviation, 
In order to be able to reject the null hypothesis,
the formula for the test statistic:
t = -6.51
P - value
P(x < 7.5) = P(z < -6.51)
Checking the p-value for z < -6.51 in the normal distribution table
P(z < -6.51) = 0.0000
p - value = 0.0000
Answer:
x = 9
Step-by-step explanation:
81/9=9
Answer:
t= 0.4933
t ≥ t ( 0.025 ,8 ) = 2.306
Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0: ud= 0 Ha: ud≠0
The significance level is set at ∝= 0.05
The test statistic under H0 is
t= d`/ sd/√n
which has t distribution with n-1 degrees of freedom
The critical region is t ≥ t ( 0.025 ,8 ) = 2.306
Computations
Student Scores before Scores after Difference d²
reading book ( after minus before)
1 720 740 20 400
2 860 860 0 0
3 850 840 -10 100
4 880 920 40 1600
5 860 890 30 900
6 710 720 10 100
7 850 840 -10 100
8 1200 1240 40 1600
<u>9 950 970 20 40</u>
<u>∑ 6930 8020 140 4840</u>
d`= ∑d/n= 140/9= 15.566
sd²= 1/8( 4840- 140²/9) = 1/8 (4840 - 2177.778) = 2662.22/8= 332.775
sd= 18.2422
t= 3/ 18.2422/ √9
t= 0.4933
Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.
C. 2 is the difference of the values of the two variables in the system of equations hope this helps!
Answer:
x=17, x=-7
Step-by-step explanation:
Step 1 :
Rearrange this Absolute Value Equation
Absolute value equalitiy entered
|x-5|-2 = 10
Another term is moved / added to the right hand side.
|x-5| = 12
Step 2 :
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |x-5|
For the Negative case we'll use -(x-5)
For the Positive case we'll use (x-5)
Step 3 :
Solve the Negative Case
-(x-5) = 12
Multiply
-x+5 = 12
Rearrange and Add up
-x = 7
Multiply both sides by (-1)
x = -7
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(x-5) = 12
Rearrange and Add up
x = 17
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
x=-7
x=17
