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steposvetlana [31]
3 years ago
13

Can someone plz help me with this one problem plz!!!

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
Dont click the linktrust me
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Help on #51 please !!
Aleks04 [339]

Answer:

53. ±6

51. 2

Step-by-step explanation:

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], in this case, evaluate everything in grouping symbols first, then evaluate the exponents to avoid confusion:

\sqrt{(32 + {2}^{3} - 4)} = \sqrt{32 + 8 - 4} = \sqrt{36} = ±6 \\  \\ (17 - 11 + {4}^{2}) \div 11 = (17 - 11 + 16) \div 11 = \\  \\ 22 \div 11 = 2

I am joyous to assist you anytime.

4 0
4 years ago
PLEASE HURRY I NEED HELP :( The area of a regular hexagon inscribed in a circle with radius 2 is
NISA [10]

Answer:

Step-by-step explanation:

4 I think not sure

8 0
3 years ago
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JulsSmile [24]

Answer: meter

Step-by-step explanation:

6 0
3 years ago
Suppose we have two bags with the numbers. Each bag has a total of 100 numbers. In the first bag there are 31 lucky numbers, in
attashe74 [19]

Answer:

There should be at most 24 lucky numbers in the third bag.

Step-by-step explanation:

Initially, there are 200 numbers. Two bags with 100 each. There are 31+18 = 49 lucky numbers. So there is a 49/200 = 0.245 probability that a randomly selected number from a random bag is the lucky number.

Now with 300 numbers, we want this probability to be lower than 24.5%. So we should solve the following rule of three:

200 - 49

300 - x

200x = 300*49

x = 1.5*49

x = 73.5

With the third bag, the probability will be the same if 73.5-49 = 24.5 lucky numbers are added. So there should be at most 24 lucky numbers in the third bag.

3 0
4 years ago
Estimate Square Root 250 to nearest TENTH!!
Bond [772]
It is 15.8 because 250 square root is 15.8...
8 0
3 years ago
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