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drek231 [11]
3 years ago
5

suzette went to the store and bought some eye liner for $2.50. two weeks later, the price of the eyeliner was increased by 50%.

what was the new price of the eyeliner
Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

$5.00

Step-by-step explanation:

Since the eyeliner went up and doubled in price, you simply multiply 2.50 by 2, and you get $5.00

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 <span>The two dice rolls are independent, so the fact that you roll an even number on the 2nd dice has no bearing on the probability that the first die shows a 1, 2, 3, or 6. Answer: 4/6 = 2/3.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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What happens to 35 when you multiply it by 100
marusya05 [52]
You times it by one and then add the two zeros so your answer is 3,500
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write the equation of the line (in slope-intercept form) that passes through the points (2,3 and (5,7)
AfilCa [17]

Answer:

The answer to your question is    y = 4/3x + 1/3

Step-by-step explanation:

Data

Point A = (2, 3)

Point B = (5, 7)

Process

1.- Calculate the slope

x1 = 2    y1 = 3

x2 = 5    y2 = 7

m = (y2 - y1)/(x2 - x1)

- Substitution

  m = (7 - 3)/(5 - 2)

- Slope

  m = 4/3

2.- Find the equation of the line

     y - y1 = m(x - x1)

     y - 3 = 4/3(x - 2)

     y - 3 = 4/3x - 8/3

     y = 4/3x - 8/3 + 3

     y = 4/3x - 8/3 + 9/3

     y = 4/3x + 1/3

8 0
3 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
2 years ago
2x+4≥24 how do I solve this problem
Katen [24]
First subtract 4 then divide 2 so u can isolate x
3 0
3 years ago
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