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nikitadnepr [17]
3 years ago
12

How to solve problem?

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

m<ADE = 57 degrees

Step-by-step explanation:

Angles of a quadrilateral add up to 360. We are already given 69 and 45, which can both be subtracted from 360, leaving us with 246. Since the two remaining angles are congruent, 246 can be divided by 2 to find the remaining measure(s). We are left with 123. However, m<ADE is supplementary to this. So we subtract 123 from 180. The final answer is 57 degrees.

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Step-by-step explanation:

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3 years ago
Any help is uselful thanks :)
Ad libitum [116K]

Answer:

4√7

Step-by-step explanation:

5√7 + √7 - 2√7

add: 6√7 - 2√7

subtract: 4√7

5 0
3 years ago
List the first 10 multiples for each number 3,4,7
notka56 [123]

Answer:

Step-by-step explanation:

3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

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3 0
3 years ago
Read 2 more answers
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
Neeed a lot of help pls answer this pls
daser333 [38]

Answer:

32

Step-by-step explanation:

100: 25

4:1

x : 8

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32: 8

ans 32

7 0
3 years ago
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