Intersection of E and A: E n A = { 8 }
Union of E and A : E U A = { -2, 3, 0, 6 , 8 }
<em><u>Solution:</u></em>
<em><u>The sets E and A are given below:</u></em>
E = { -2, 3, 8 }
A = { 0, 6 , 8 }
<em><u>Find the intersection of E and A</u></em>
Intersection of E and A means that, set containing all elements of E that also belong to A
Therefore,
From sets E and A,
E n A = { 8 }
<em><u>Find the union of E and A</u></em>
union of E and A contains all elements of set E and set A
E U A = { -2, 3, 0, 6 , 8 }
Answer:
-0.625 unit
Step-by-step explanation:
Given that:
where;
p = price
q = quantity
To find the rate of change of quantity (q) with respect to price (p) we go by the differentiation
when P =40
Then 4(q+3)² = 100, 000
(q+3)² = 
(q+3)² = 25,000
(q+3) = 
q+ 3 = 50
q = 50 -3
q = 47
NOW;
Thus, the rate of change of quantity with respect to price when p = $40 is -0.625 unit.
Answer:
t=21
Step-by-step explanation:
Answer:
60 points in 5 games
Step-by-step explanation:
plug the numbers of points scored into the top boxes, so the boxes should look like ( [8]+[11]+[12]+[16]+[n] ) then plug in the number of games he played in the bottom box [5] so 8+11+12+16+n all divided by 5 has to = 12
5x12 = 60
n= 60-8-11-12-16 n= 13
The answer to this question is D
