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Alex Ar [27]
3 years ago
10

Complete the equation describing how

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

y=x+<em>5</em><em> </em>is the correct answer.

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Let f(x) = [infinity] xn n2 n = 1 . Find the intervals of convergence for f. (Enter your answers using interval notation.) Incor
sveta [45]

Answer:

The interval of convergence is -1<x<1

Step-by-step explanation:

To find the interval of convergence of the series, we will use the condition for convergence of a series according to Ratio test.

The solution is as shown in the attachment.

7 0
3 years ago
Use the drawing tool(s) to form the correct answers on the provided graph.
lianna [129]

Answer:

  see below

Step-by-step explanation:

A graphing calculator can help you do this.

__

The function crosses the y-axis where x=0.

  g(0) = -5^0 +5 = -1 +5

  g(0) = 4

The function crosses the x-axis where g(x) = 0

  0 = -5^x +5

  5^x = 5 = 5^1

  x = 1

  g(1) = 0

The points of interest are (0, 4) and (1, 0).

7 0
3 years ago
What is 2x/3 - 4 =x ?
Inessa [10]

Step-by-step explanation:

2x/3 -4 = x

multiply both side by 3

2x - 12 = 3x

-x = 12

x = -12

3 0
3 years ago
Simplify the expression. 2+2^2÷4+3 6 7 21 67
True [87]

Answer:

6

Step-by-step explanation:

2+2^2÷4+3

PEMDAS says exponents first

2+4÷4+3

Then multiply and divide from left to right

2+1+3

Then add and subtract

6

3 0
3 years ago
Usebthe elimination method to solve the following system of equations<br>4x+y=13<br>5x-y=5​
pochemuha

Answer:

x = -2, y = 21

Step-by-step explanation:

Let 4x + y = 13 to be equation1 {eqn1}

and let 5x - y = 5 to be equation2 {eqn2}

Using elimination method, you would try to make sure a particular unknown has the same value in both equation 1 and 2. This would make it easy for you to subtract one equation from the other.

Notice how the value of y is the same in both equations. That's a good sign.

But the signs aren't the same. Meaning y in eqn1 has a value of +1, and y in eqn2 has a value of -1. We need to make them similar.

So, we multiply the value of y in eqn1 by all the terms in eqn2. And, do pretty much the same thing by multiplying the value of y in eqn2 by all the terms in eqn1.

You would have:

-1 * (4x + y = 13)

+1 * (5x - y = 5)

This would result in;

-4x -  y = -13 (eqn3)

5x - y = 5 (eqn4)

So, just subtract eqn3 from 4

You would have;

(5x - -4x) + (-y -- y) = (-13 - 5)

9x + 0 = -18

x = -18/9 = -2

and to find y;

just substitute the value of x into any of the 4 equations. let's try equation 1

Therefore;

4(-2) + y = 13

-8 + y = 13

y = 13 + 8 = 21

8 0
3 years ago
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