1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
11Alexandr11 [23.1K]
3 years ago
14

Determine the domain and range of the graph below.

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

Last one

Step-by-step explanation:

You might be interested in
Simplify.
UkoKoshka [18]
(x^2 - 3x + 1) - (x^2 + 2x + 7)
Distribute the negative
x^2 - 3x + 1 - x^2 - 2x - 7
Combine like terms
-5x - 6
3 0
3 years ago
- 7th Grade Work -<br><br> Am I doing this correctly?
katrin2010 [14]

Answer:

yes i think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do we calculate 25% of 300
Natali5045456 [20]
25% is equal to \frac{1}{4}. To get 25% of 300, we multiply 300 by either 0.25 or \frac{1}{4}. This gives us (300)( \frac{1}{4}) =  \frac{300}{4}  =  \frac{150}{2} = 75
4 0
3 years ago
Read 2 more answers
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
Please help me with ptomblem
marysya [2.9K]

Answer:

When p^2 - 4p is subtracted from p^2 + p - 6, the result is 5p - 6. To get p - 9, subtract 4p + 3 from the result.

Step-by-step explanation:

✔️Subtracting p^2 - 4p from p^2 + p - 6:

(p^2 + p - 6) - (p^2 - 4p)

p^2 + p - 6 - p^2 + 4p (Distributive property)

Collect like terms

p^2 - p^2 + p + 4p - 6

5p - 6

✔️Subtracting p - 9 from 5p - 6:

(5p - 6) - (p - 9)

5p - 6 - p + 9 (distributive property)

Add like terms

4p + 3

3 0
2 years ago
Other questions:
  • I need help with the puzzle plsssss it’s due Wednesday!
    14·2 answers
  • How do u write 23f in verbal expression
    11·1 answer
  • Estimate how many 12 inch rulers will be about the same length as a sheet of paper
    12·2 answers
  • The diagram of the hexagon below displays all the lines of symmetry for the hexagon. True or false
    6·2 answers
  • Solve for X and Y in the figure below. Thank you!
    8·1 answer
  • Find the length of MN
    11·1 answer
  • A. Right B. Isosceles C. Obtuse O D. Equilateral E. Scalene F. Acute​
    13·1 answer
  • A volunteer group picked up 3 times as many plastic bottles as cans in their community. The number of papers they picked up was
    6·1 answer
  • SOMEONE PLEASE HELP ME WITH THIS!!<br> IMAGE DOWN BELOW!!<br> ILL GIVE YOU BRAINLIST ANSWER!!
    15·1 answer
  • A dog won a race at the local fair by running 7 1/4 miles in exactly 2 hours. At this constant rate, how long does it take the s
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!