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11Alexandr11 [23.1K]
3 years ago
14

Determine the domain and range of the graph below.

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

Last one

Step-by-step explanation:

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Slav-nsk [51]

Answer:

5

Step-by-step explanation:

answer my last question plz

4 0
2 years ago
Read 2 more answers
Simplify <br><img src="https://tex.z-dn.net/?f=%285%20%2B%201%29%20%5E%7B2%7D%20%20-%20%2811%20%2B%203%20%5E%7B2%7D%20%29%20%5Cd
Elodia [21]

Answer:

31

Step-by-step explanation:

Evaluate following the order set out in the acronym PEMDAS

That is parenthesis, exponents, multiplication, division, addition, subtraction

Given

(5 + 1)² - (11 + 3² ) ÷ 4

= 6² - (11 + 9) ÷ 4

= 36 - 20 ÷ 4 ← division before subtraction

= 36 - 5

= 31

6 0
3 years ago
PLEASE HELP I WILL GIVE YOU BRAINLIEST
fredd [130]

Answer:

I think the distance between b and c is 3.

Step-by-step explanation:

5 0
2 years ago
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part
Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range          

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{8726}{20} = 436.3

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

S.D = \sqrt{\frac{75924.2}{19}} = 63.21

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Median = \frac{431 + 437}{2} = 434

Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482

IQR = 482 - 395 = 87

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

Mean =\displaystyle\frac{8406}{20} = 420.3

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

S.D = \sqrt{\frac{247636.2}{19}} = 114.16

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

Median = \frac{431 + 437}{2} = 434

Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482

IQR = 482 - 395 = 87

Thus. the standard deviation increased but there was no change in the interquantile range.

5 0
3 years ago
IF SOMEONE ANSWERS WITHIN 5 MINUTES THEY WILL GET BRAINLIEST ANSWER
Liula [17]

Answer:

A

Step-by-step explanation:

Hi!

This one's a bit hard to explain! IF you want explanation, just comment.

Using the data given, we can conclude that \boxed{A} is the correct answer.

Hope this helps!

6 0
3 years ago
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