Verify that A(3, 1), B(0, 5), and C(-1, -1) are the vertices of a right triangle.

Determine the amplitude of the function y = 2 cos x from the graph shown below:

kirill115 [55]

4 is the answer I had the same question

8 0

3 years ago

Gamma rays have the longest wavelength on the electromagnetic spectrum.

Serhud [2]

-- False. Gamma rays have the shortest wavelengths
on the electromagnetic spectrum.

-- A disturbance that transfers energy from place to place
is called a wave.

3 0

3 years ago

The area of the window is 54 ft.². Find the dimensions in feet. Width is (2x-3)ft and length is x ft.

denis-greek [22]

Answer:

34

Step-by-step explanation:

because multiply 54 feet is what you get is 34

5 0

3 years ago

What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?

Arisa [49]

Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³

8 0

3 years ago

An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of

Helga [31]

Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = $\pi r^{2} \frac{h}{3}$

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

$r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm$

We will now find the volume of the cone.

Volume of cone $\pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}$

We know the density of ice is 0.93 grams per $1cm^{3}$

$1cm^{3} =0.93g\\\frac{168175\pi }{24} cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g$ (Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = $\pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}$

Volume of cone being melted = New Volume - Original volume

= $\frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}$

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = $\pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}$

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = $5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}$

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= $\frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}$

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

4 0

2 years ago