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Feliz [49]
3 years ago
7

Verify that A(3, 1), B(0, 5), and C(-1, -1) are the vertices of a right triangle.

Mathematics
1 answer:
Zina [86]3 years ago
4 0
No, not a right triangle
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How is the quotient of 3,419 and 11 determined using an area model? Enter your answers in the boxes to complete the equations. 3
Ipatiy [6.2K]

The quotient of 3,419 and 11 is 310.81.

<h3>How to illustrate the information?</h3>

It should be noted that from the information given, we are to find the quotient of 3,419 and 11 determined using an area model.

It should be noted that this simply means the division of the values given. This will be:

= 3419/11

= 310.81

Therefore, the quotient of 3,419 and 11 is 310.81.

Learn more about quotient on:

brainly.com/question/11916238

#SPJ1

6 0
1 year ago
Hey you can help me out with this
iogann1982 [59]

Answer:

Step-by-step explanation:

To find the angles of any shape with all sides equal in length, we use the formula:

    \frac{(n-2)*180}{n} , where n is the number of sides

For a pentagon, we get the equation:

\frac{(5-2)*180}{5}= 108 degrees

Thus the measure of each in a pentagon if the lengths of all five sides are equal is 108 degrees.

Hope that helps!

6 0
2 years ago
Read 2 more answers
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
△DEF is rotated about point N to △D′E′F′ .
MatroZZZ [7]

the answer is d the image is the same size


6 0
3 years ago
Draw an obtuse angle big. place a point p inside the angle. now construct perpendiculars from the point to both sides of the ang
never [62]

I have drawn three obtuse angles showing three different positions.

then taken a point p inside it.

Now to draw perpendicular from a point to a given line

we draw a line parallel fom that point to that given line.

After that from that point we draw perpendicular to that line.

Now the question arises which side is closer to point p ,

The answer is if length of perpendicular from p to the line is longer that side is farther from the point p , and if the length of perpendicular is shorter then that that line is nearer to point P.

8 0
3 years ago
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