All categories

3 years ago

What are the solutions to the equation (x-2)(x + 5) = 0?

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

Step-by-step explanation:

A product of two (or more) factor can be zero if and only if at least one of the factors is zero.

In other words, you cannot multiply two non-zero real numbers, and have zero as a result.

So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

x-2=0 x=2

The second factor is zero if

x + 5 = 0 x= -5

You might be interested in

Here is a circle touching a square.

Alex Ar [27]

Answer: 9πcm²

Step-by-step explanation: area of the square= 36cm²

Therefore, the area of one side= √area = √36 = 6cms

Since the circle is touching the sides of the square, the side of the square = the diameter of the circle

Therefore the radius of the circle= side/2 = 3cm

The formula for the ares of the circle is πr²

π*3*3 = 9πcm²

8 0

3 years ago

-3(3x-8) apply distributive property

madreJ [45]

Answer:

-9x+24

Step-by-step explanation:

Multiply using the distributive property. Hope this helps :)

3 0

3 years ago

F(x)=2x^2 -5 , simplify f(x+h)/h , where h≠0

7nadin3 [17]

Answer:

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}$

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}$

Step-by-step explanation:

$f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0$

4 0

2 years ago

use the elimination method to solve the system of equations choose the correct ordered pair -x + y = -2 2x - 3y = 4

mafiozo [28]

Answer:

The answer is (2, 0).

I hope this helps!

8 0

3 years ago

The sides of a triangle are represented by The expressions 2x ^2+4 , 5x^2-6x and 8x+3 determine the perimeter of the triangle

vaieri [72.5K]

Answer:

Im not sure

Step-by-step explanation:

Sorry

3 0

3 years ago