What are the solutions to the equation (x-2)(x + 5) = 0?
1 answer:
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Answer:
<h3>Option A is the correct option.
Step-by-step explanation:
Let the number be 'x'
Let's create an expression:
The number or alphabet by which variable is multiplied is called the coefficient of the term.
In our case, The value of coefficient is 6
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Follow PEDMAS:
Parenthesis
Exponents
Division/Multiplication
Addition/Subtraction
Multiply 99*99.
Subtract from Left to Right.
The Answer Is:
Hope this helps.
-Benjamin
Follow PEDMAS:
Parenthesis
Exponents
Division/Multiplication
Addition/Subtraction
Multiply 99*99.
Subtract from Left to Right.
The Answer Is:
Hope this helps.
-Benjamin
A graph shows the function can be factored as
f(x) = (x -1)((x-8)² +1)
There is one real root and there are two complex roots. The latter can be found from the vertex form factor:
(x - 8)² + 1 = 0
(x - 8)² = -1
x - 8 = ±√(-1) = ±i
x = 8 ± i
The zeros of the function are {1, 8-i, 8+i}.
f(x) = (x -1)((x-8)² +1)
There is one real root and there are two complex roots. The latter can be found from the vertex form factor:
(x - 8)² + 1 = 0
(x - 8)² = -1
x - 8 = ±√(-1) = ±i
x = 8 ± i
The zeros of the function are {1, 8-i, 8+i}.