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3 years ago

What are the solutions to the equation (x-2)(x + 5) = 0?

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

Step-by-step explanation:

A product of two (or more) factor can be zero if and only if at least one of the factors is zero.

In other words, you cannot multiply two non-zero real numbers, and have zero as a result.

So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

x-2=0 x=2

The second factor is zero if

x + 5 = 0 x= -5

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Which of the following is in the solution set of y< 8 x− 3? Select one: (7, 46) (7, 60) (10, 89) (9, 82)

navik [9.2K]

Answer:

(7, 46)

Step-by-step explanation:

The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...

x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not

x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set

x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set

Of the choices offered, only (7, 46) is in the solution set.

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3 years ago

What are the coordinates of point A? X (8,-6) 0 (-6, 8) (-5, 7) (7-5)

AlexFokin [52]

Answer:

c is the correct one

Step-by-step explanation:

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3 years ago

Need help fast!

amm1812

Answer: A) Point B, because if cups of frosting are 50, then drops of food coloring will be 200.

This is because the proportion of frosting to food coloring is 1:4, and if the answer to A is simplified (50:200), the ratio would be the same.

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3 years ago

Read 2 more answers

Of the 800 participants in a marathon 220 are running to raise money for a cause. How many participants out of 100 are running f

nadezda [96]

Answer:

27.5 /100 are running for a cause

Step-by-step explanation:

We know that 220/800 are running for a cause

Divide the top and bottom by 8 to get the fraction out of 100

220 /8 =27.5

800/8 = 100

27.5 /100 are running for a cause

7 0

3 years ago

NEED ANSWERS ASAP, 100 POINTS! There are twenty classes at each of two middle schools. The number of students in each class at e

DiKsa [7]

Note: You missed to add the dot plots chart. As I found the chart after a little research. Thus, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.

Answer:

'There are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

Step-by-step explanation:

From the diagram, it is clear that

The data set containing Poplar Middle School:

20 20 20 21 21 21 21 21 22 22 22 22 22 22 22 23 23 23 23 24

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$\mu = 435/20$