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3 years ago

Please help me with this problem

Mathematics

1 answer:

Feliz [49]3 years ago

7 0

Answer:

2nd one, 3rd one and last one

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are u suppose to find a common denominator when multiplying fractions? (dont answer the question in the picture just answer if u

Shalnov [3]

Answer:

Step-by-step explanation:

you multiply straight across on top and bottom then you simplify :)

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3 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

2 years ago

2x - 3y = 16 5x - 3y = 13

stepan [7]

AAAASAAAAAAAAAAAAAAhdhddhd

5 0

2 years ago

Find the number of 4-digit numbers that contain exactly two even and two odd digits.

Dvinal [7]

Answer:

2,435

Step-by-step explanation:

find two even and two odd

7 0

3 years ago

Willie found shirts at a back-to-school sale for $15.25 each. He also found jeans on sale for $32.95 per pair. He purchased 3 sh

Brilliant_brown [7]

Answer:

111.65

Step-by-step explanation:

$15.25 x 3 = $45.75

$32.95 x 2 = $65.9

Total: $111.65

8 0

3 years ago

Read 2 more answers