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Arte-miy333 [17]
2 years ago
10

What is the acceleration of a 24 kg mass pushed by an 8N force?​ Someone help me

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

Answer:

Acceleration=3

Step-by-step explanation:

Formula for solving acceleration: F = ma

8N=24

N=24/8

N=3

I think this is correct :)

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PLEASE HELP THIS IS EASY BUT IM JUST BAD AT MATH
balandron [24]

Answer:

Its B

Step-by-step explanation:

Try and read throught it slowly and everytime you hit a variable go down the the answer and find where it is. That helped me a lot

5 0
2 years ago
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Apply the distributive property to factor out the greatest common factor. 12+20=
Rina8888 [55]

Answer: 12+20 = 12 + 20 = 4(3+5)

Step-by-step explanation:

3 0
3 years ago
Mike can stitch 7 shirts in 42 hours. he can stitch 1 shirt in how many hours, and in 1 hour he can stitch how much of a shirt.
podryga [215]

Answer:

Mike can stitch one shirt in 6 hours and in 1 hour he can stitch \frac{1}{6} (0.167) shirts.

Step-by-step explanation:

Mike can stitch 7 shirts in 42 hours

to calculate the time that he takes to make 1 shirt, we have to divide 42 by 7.

He can stitch 1 shirt in = \frac{42}{7} = 6 hours

Now we calculate the work done in one hour.

He can stitch in 1 hour = \frac{1}{6}  shirts or 0.167 shirts

Mike can stitch one shirt in 6 hours and in 1 hour he can stitch \frac{1}{6} shirts.

5 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. 3x2 - 10 = 0. A) Double root B) R
Mademuasel [1]

1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3  [imaginary root]


2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41  [real and irrational root]


3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0    [double root]


Read more on Brainly.com - brainly.com/question/1698047#readmore




hope it helps

4 0
2 years ago
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