Answer:
Its d 5/10
Step-by-step explanation:
The function that represents how much more water can be added to the bucket before it overflows is given as follows:
c(x) = 6x³ + 3x² - 2x - 2.
<h3>How to define the function?</h3>
The function to calculate the space remaining in the pool is given by the subtraction of the capacity function by the function representing the current amount of water in the pool.
The functions in this problem are defined as follows:
- f(x) = 8x³ + 4x² - 6x + 5.
- g(x) = 2x³ + x² - 4x + 7.
Then the capacity function is obtained as follows:
c(x) = f(x) - g(x)
c(x) = 8x³ + 4x² - 6x + 5 - (2x³ + x² - 4x + 7)
Then the distributive property is applied to the negative sign as follows:
c(x) = 8x³ + 4x² - 6x + 5 - 2x³ - x² + 4x - 7.
Finally, the like terms are combined, that is, the terms that have the same variable and exponent, as follows:
c(x) = 6x³ + 3x² - 2x - 2.
More can be learned about operations with functions at brainly.com/question/2723982
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It's a proportion. Set it up as 3/30 * x/11= 1.1
Answer:
A =90 in^2
Step-by-step explanation:
The area of the rhombus is found by
A = 1/2 d1 * d2 where d1 and d2 are the diagonal lengths
d1 = 2*6 =12
d2 = 2 *7.5=15
A = 1/2 (12*15)
A =90 in^2
