I set this up as an inequality,
. If you take the cubed root of 800, you get the lower bound of the side length, which is 9.2. Then I just worked my way up until I hit the first number that put me over a volume of 800. That number is 9.29, because 9.28 cubed is 799.1 (not high enough) and 9.29 cubed is 801.8. Therefore, the bounds of the sides exist within a conjunction:
. That's the best I could come up with to help on that one. Wasn't sure if there was another method you were taught at school. I just used common sense more than any rule.
<h2>
Explanation:</h2>
Let's use a trial and improvement method to find this solution.
Step 1. Let's choose x = 8.5
Substituting into the equation:
Step 2. Let's choose x = 8.4
Substituting into the equation:
Step 3. Let's choose x = 8.3
Substituting into the equation:
Since the sign of the equation changes from positive to negative when evaluating from 8.4 to 8.3, then x = 8.3 seems to be a reasonable value. Finally, the solution to 1 decimal place is:
6(Mathhony’s b). Just multiply matthonys boxes by 6
Answer:
5,10 ,15,20,25,30,35,60,65,70,75,80,85
Step-by-step explanation:
IT WOULD BE 85
Given:
The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).
To find:
The perimeter of quadrilateral ABCD.
Solution:
Distance formula:
Using the distance formula, we get
Similarly,
And,
Now, the perimeter of the quadrilateral ABCD is:
Therefore, the perimeter of the quadrilateral ABCD is 20 units.