The answer is 60 (wow this was a fast answer wish people answered my questions this fast)
Answer:

Step-by-step explanation:
A square is a <u>shape that which all sides are equal</u>
<em>14 is one side of the square and to find the area of a square/rectangle, you do </em><u><em>length*width </em></u>
14*14=196
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC;
in triangle ΔFGH;
Segment
= 14
Segment
= 14
Segment
= 27
Segment
= 19
Segment
= 19
Segment
= 2·y + 5
∡A = 32°
∡G = 32°
∡A = ∠BAC which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴
=
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
Answer:
HJ = 17
IK = 30
Step-by-step explanation:
to find HI :
GH : 2
HI : ?
IJ : 12
GI : 7
HI = GI - GH
HI = 7- 2
HI = 5
HI + IJ = HJ
5 + 12 = HJ
17 = HJ
To find IK
IJ = ?
JK = 12
KL = ?
IL = 49
JL = 31
To find IK we need to find KL and IJ
KL = JL - JK
KL = 31 - 12
KL = 19
IJ = IL - (JK + KL)
IJ = 49 - 31
IJ = 18
IK = IJ + JK
IK = 18 + 12
IK = 30