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3 years ago

An airplane travels at a constant speed of 320 miles per hour how far in miles will the airplane travel in 15 minutes

Mathematics

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:

80 Miles

Step-by-step explanation:

If you convert 15 minutes to hours, you get .25 hours. Then, you use that number and multiply it by 320 to get your answer; 80 miles.

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-t+5=t-19<br> Need an answer and a work pls!

Nadusha1986 [10]

Answer:

t=12

Step-by-step explanation:

Step 1: Subtract t from both sides.

−t+5−t=t−19−t

−2t+5=−19

Step 2: Subtract 5 from both sides.

−2t+5−5=−19−5

−2t=−24

Step 3: Divide both sides by -2.

−2t−2=−24−2

8 0

3 years ago

Find the value of x so that m||n

jasenka [17]

Answer:x=17

Step-by-step explanation:

Set 6x+5+5x-12 equal to 180

Simplify into 11x-7=180

Add 7 to both sides to get 11x=187

Divide both sides by 11 to get x=17

8 0

2 years ago

Read 2 more answers

There are 3072 books in the school library if 96 students reads the same number of books how many books would each student need

s2008m [1.1K]

Answer:

32 books each

Step-by-step explanation:

5 0

2 years ago

Please help me with this homework

Leya [2.2K]

Answer:

Step-by-step explanation:

10^2+3^2=109 and sqrt 109 getting 10.4

3 0

3 years ago

Use the Quadratic Formula to solve the equation. (Enter your answers as a comma-separated list.) 13x^2 +1 = -10

12345 [234]

Step-by-step explanation:

The given quadratic equation is :

$13x^2 +1 = -10x\\\\or\\\\13x^2+10x+1=0$

The formula to solve a quadratic equation is :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Put a = 13, b = 10 and c = 1

So,

$x=\dfrac{-10\pm \sqrt{10^2-4(13)(1)} }{2(13)}\\\\x=-0.118, -0.651$

Hence, this is the required solution.

3 0

3 years ago