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Furkat [3]
3 years ago
15

Andrea ran 1.04 kilometers more on Wednesday than she ran on Thursday.

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

Answer:

thanks for the points little sis

Step-by-step explanation:

ivanzaharov [21]3 years ago
6 0

Answer:

DONT TAKE THIS OFF

Step-by-step explanation:

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What are the first 3 composite numbers that are multiples of 4 and greater than 10.
insens350 [35]

Answer:

12, 16, and 20

Step-by-step explanation:

These are the answers because:

1) Composite numbers mean numbers that are divisible by more than two numbers (1 and itself).

2) Multiples of 4 that are greater than 10 are: 12, 16, and 20 because they are all divisible by more than two numbers, they are greater than 10, and they are mutiples of 4. You can check if they are multiples of 4 by skip counting or multiplying: 4, 8, 12, 16, 20 or 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20.

Therefore, the answers are: 12, 16, and 20

Hope this helps! :D

7 0
3 years ago
Read 2 more answers
Michelle is a server in a restaurant. On a weekend night, Michelle earned $4 an hour and $65 in tips She made a total of $93 Wri
Sedbober [7]

Answer:worked 7 hours

Step-by-step explanation:

93 - 65 = 28

28/4 = 7 hours

6 0
3 years ago
Read 2 more answers
(4 + 7w2)
ivanzaharov [21]
Answer: 18w^2 - 6w + 4

Explanation:

(4 + 7w^2) - (6w - 11w^2)
= 4 + 7w^2 - 6w + 11w^2
= 18w^2 - 6w + 4
5 0
3 years ago
Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°
Zepler [3.9K]
Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}

\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}&#10;\\\\\\&#10;therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}&#10;\\\\&#10;-------------------------------\\\\&#10;sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13}  \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}
3 0
3 years ago
Find the m∠DCA A. 10 B. 29 C. 116 D. 40
Blizzard [7]
DCA is 116 because x=29, when you plug 29 into x you get 116
5 0
3 years ago
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