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VikaD [51]
3 years ago
14

Niles and Bob sailed at the same time for the same length of time. Niles' sailboat traveled 36 miles at a speed of 6 mph, while

Bob's motorboat traveled 96 miles at a speed of 16 mph. For how long were Niles and Bob traveling?
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

Niles and Bob were traveling for 6 hours.

Step-by-step explanation:

The speed or rate at which an object is moving can be computed using the formula:

s=\frac{d}{t}

Here:

<em>s</em> = speed

<em>d</em> = distance traveled

<em>t</em> = time taken

It is provided that Niles and Bob sailed at the same time for the same length of time.

Speed of Niles sailboat is, <em>s</em>₁ = 6 mph.

Distance traveled by Niles' sailboat is, <em>d</em>₁ = 36 miles.

Speed of Bob's sailboat is, <em>s</em>₂ = 16 mph.

Distance traveled by Bob's sailboat is, <em>d</em>₂ = 96 miles.

It took both Niles and Bob the same time to travel the respective distance.

Compute the time it took Niles to travel 36 miles at 6 mph speed as follows:

t_{1}=\frac{d_{1}}{s_{1}}

   =\frac{36}{6}\\=6

It took Niles 6 hours to travel 36 miles at 6 mph speed.

Compute the time it took Bob to travel 96 miles at 16 mph speed as follows:

t_{2}=\frac{d_{2}}{s_{2}}

   =\frac{96}{16}\\=6

It took Bob 6 hours to travel 96 miles at 16 mph speed.

Thus, Niles and Bob were traveling for 6 hours.

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