Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es = \sqrt{ \frac{p(1-p)}{n} }
where
n = the sample size.
The margin of error is
E=z^{*}E_{s}
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
6+7+8
6+8+7
7+6+8
7+8+6
8+7+6
8+6+7
Answer:
720 - 1 x 2 x 3 x 4 x 5 x 6
0.14% - 1/170
Answer:
d
Step-by-step explanation:
x/7 <2
Multiply both sides if the inequality by 7
x/7×7 < 2×7
Then cancel out the 7s from x/7×7 to get x by itself
now
x < 14
Answer:
0.336 or 33.6%
Step-by-step explanation:
It follows from the question that the probability of a complaint is 35% = 35/100 = 0.35. Let's call this probability, p.
The probability of no complaint is mutually exclusive of p since both are complements. Let's call this q. Then
q = 1 - p = 1 - 0.35 = 0.65
The distribution is a binomial distribution.
Events of each call are independent.
The probability of 2 calls with complaint out of 5 is
