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yan [13]
3 years ago
11

Given that g(x)=3x^2 -4x+3, find each of the following. PICTURE DOWN BELOW!!!

Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

To evaluate the expression for the given values.

Substitute the given values for x into g(x)

a

g(0) = 3(0)² - 4(0) + 3 = 0 - 0 + 3 = 3

b

g(- 1) = 3(- 1)² - 4(- 1) + 3 = 3 + 4 + 3 = 10

c

g(2) = 3(2)² - 4(2) + 3 = 12 - 8 + 3 = 7

d

g(- x) = 3(- x)² - 4(- x) + 3 = 3x² + 4x + 3

e

g(1 - t)

= 3(1 - t)² - 4(1 - t) + 3

= 3(1 - 2t + t²) - 4 + 4t + 3

= 3 - 6t + 3t² - 4 + 4t + 3

= 3t² - 2t + 2

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1 year ago
WILL GIVE BRAINLIEST
Papessa [141]
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t

acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18

</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s

acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
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