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olganol [36]
3 years ago
5

Find the 10th term of the geometric sequence 10, -50, 250, ...

Mathematics
2 answers:
dedylja [7]3 years ago
6 0

Answer:

-19,531,250

Step-by-step explanation:

multiply the last term by -5

OlgaM077 [116]3 years ago
6 0

Answer:

it is -19531250

Step-by-step explanation:

the person above was right i just wanna remind anyone using de1ta ma1h that you can't put commas between the numbers or it'll be wrong which doesn't make any sense but it's part of the program ig

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Help with this math question... Leslie created a rectangle on the coordinate plane. Three of the vertices are (5,-2), (5,2), (2,
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Draw the points on a graph, you will have three points and need to add the fourth to make the corners of a rectangle. After you have found the point on the missing corner of the rectangle see what its x and y coordinates are.


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Aaron wants to buy a bicycle that costs $128. So far he has saved $56 the equation of 8 + 56 equal 128 can be used to find the a
lutik1710 [3]

Answer:

Aaron still needs to save $9

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What is the value of x in the equation (x + 12) = (x + 14) – 3?
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Read 2 more answers
There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

-

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
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