find three consecutive number whose sum shall equal 45
I thought i know but i don’t sorry
9^1/3 * 3^x = 27^4/5
Rewrite 9 as 3^2
(3^2)^1/3 * 3^x = 27^4/5
Multiply the exponents in the first term:
3^2/3 * 3^x = 27^4/5
Use power rule to combine exponents:
3^(2/3 +x) = 27^4/5
Rewrite the 2nd term:
3^(2/3 +x) = (3^3)^4/5
Set the exponents only to equal:
2/3 + x = 3(4/5)
Solve for x:
simplify the right side:
2/3 + x = 12/5
Subtract 2/3 from both sides:
x = 26/15
To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
To find the y-intercept, set x = 0 \displaystyle x=0 x=0.
Hope this helped brainliest is appreciated