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tatyana61 [14]
3 years ago
7

La base de una cartulina rectangular mide 8 cm de altura si le recortamos 3 cm a su altura el area de la nueva cartulina seria 1

26 cm calcula las dimenciones de la cartulina inicial
Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

w=8cm\\h=18.75cm

Step-by-step explanation:

Let:

w=Width\\h=Initial\hspace{3}height\\h_m=Modified\hspace{3}height\\\\Where:\\\\h_m=h-3

The area of the cardboard can be calculated using the formula to find the area of a rectangle:

A=w*h

The area of the new cardboard would be:

A=w*h_m\\\\Where:\\\\w=8\\h_m=h-3\\A=126

So:

126=8*(h-3)\\\\126=8h-24

Solving for h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Therefore, the dimensions of the initial cardboard are:

w=8cm\\h=18.75cm

<u><em>Translation:</em></u>

Sea:

w=Ancho\\h=Altura\hspace{3}inicial\\h_m=Altura\hspace{3}modificada\\\\Donde:\\\\h_m=h-3

El área de la cartulina se puede calcular usando la fórmula para encontrar el área de un rectángulo:

A=w*h

El área de la nueva cartulina sería:

A=w*h_m\\\\Donde:\\\\w=8\\h_m=h-3\\A=126

Entonces:

126=8*(h-3)\\\\126=8h-24

Resolviendo para h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Por lo tanto, las dimensiones de la cartulina inicial son:

w=8cm\\h=18.75cm

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Explain why the equation 5(2x+1)-2=6x+5 has only one solution. Then find the solution.
netineya [11]

Answer:

10x + 3 = 6x + 5

Based on this, we have the lines y=10x+3 and y=6x+5. Both of the equations are linear, so they are straight lines when graphed. A system of straight lines can only have one solution maximum.

Solution:

x = 1/2

y = 8

(1/2 , 8)

Step-by-step explanation:

Start by expanding with the distributive property, then simplify by collecting like terms.

5(2x + 1) - 2 = 6x + 5     Multiply "5" with each term in the brackets.

10x + 5 - 2 = 6x + 5       Collect left side's like terms (5 - 2 = 3)

10x + 3 = 6x + 5

Based on this, we have the lines <u>y=10x+3 and y=6x+5</u>. A solution is the same as the POI (point of intersection). Both of the equations are linear, so they are straight lines when graphed. A system of straight lines can only have one solution maximum.

Some linear systems might have no solutions (when the lines are parallel) or infinite solutions (when the lines are equivalent, the same).

To find the solution, continue with the equation and isolate "x". This will give you the x-coordinate of the point of intersection.

To isolate 'x', move everything to the other side of 'x'. To move something, you do its reverse operation to both sides in reverse BEDMAS order.

10x + 3 = 6x + 5

10x - 6x + 3 = 6x - 6x + 5     Subtract 6x from both sides

4x + 3 = 5     "6x" cancelled out on the right. Simplified left (10x-6x=4x)

4x + 3 - 3 = 5 - 3      Subtract 3 on both sides. "3" on the left will cancel out

4x = 2      The right side was simplified (5 - 3 = 2).

4x/4 = 2/4      Divide both sides by 4 to isolate 'x'. Simplify right side.

x = 1/2          Solution's x-coordinate

Substitute what you found for 'x' into any equation that has 'y' (either <u>y=10x+3 or y=6x+5</u>). I will choose the first equation.

y = 10x + 3      

y = 10(1/2) + 3        Multiply 1/2 and 10

y = 5 + 3       Add

y = 8          Solution's y-coordinate

Therefore the solution is when x=1/2 and y=8, or as an ordered pair, (1/2 , 8).

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A car is purchased for $27,000 . After each year, the resale value decreases by 30% . What will the resale value be after 3 year
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An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
Flura [38]

Answer:

The width of the art projects of area 63.6 square inches is 7.97 inches .

Step-by-step explanation:

Given as :

The area of the square art project = 63.6 square inches

Since The shape of the art project is square

So, The Area of square = A = side × side = side²

Now, let the measure of the width of art project = w inches

I.e side = w inches

or ,  A  = side²

Or , A = w²

Or, 63.6 = w²

So, w = \sqrt{63.6}

I.e w = 7.97 inches

So, the width of the projects = w = 7.97 inches

Hence The width of the art projects of area 63.6 square inches is 7.97 inches . Answer

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The (m-3)^2 is equivalent to <br> 1. m^2 + 9<br> 2. m^2 - 9<br> 3. m^2 - 6m + 9<br> 4. m^2 - 6m - 9
Deffense [45]

The value of the expression (m-3)² will be m² - 6m + 9. The correct option is 3.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The value of the expression (m-3)² will be solved by using the quadratic formula as below:-

( a - b )² = a² -2ab + b²

(m-3)²  = m² - 2 x 3 x m + 9

(m-3)²  = m² - 6m + 9z

Therefore, the value of the expression (m-3)² will be m² - 6m + 9. The correct option is 3.

To know more about Expression follow

brainly.com/question/723406

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2 years ago
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