<span>common difference for the sequence = 1/16
cause
1/4 = 4/16
and
3/8 = 6/16
so
4/16 + 1/16 = 5/16
5/16 + 1/16 = 6/16
</span>
80% of 7.5 is 6.
so if he travelled 80% further, it would be 7.5+6 which is
13.5
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
It's the first one.
If you work backwords, I'd say it's easier. 3y swuared is 9y2, and 11 squared is 121. Then just keep the sign the same
See the attached picture for the answers.
