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Gelneren [198K]
3 years ago
13

Please help me with this equation

Mathematics
1 answer:
klasskru [66]3 years ago
4 0

Answer: \dfrac{1}{16}x^{-5}y^{-2}z^{4}

Step-by-step explanation:

Given

Expression is \left(4xy^3z^{-2}\right)^{-2}\cdot x^{-3}y^4z^0

using the Exponent property that is

[(a)^b]^c=a^{b\cdot c}\\a^x\cdot a^y=a^{x+y}

Applying the above property

\Rightarrow \left(4xy^3z^{-2}\right)^{-2}\cdot x^{-3}y^4z^0=4^{-2}x^{-2}y^{-6}z^{4}\cdot x^{-3}y^4z^0\\\\\Rightarrow \left(4xy^3z^{-2}\right)^{-2}\cdot x^{-3}y^4z^0=4^{-2}x^{-2-3}y^{-6+4}z^{4+0}\\\Rightarrow 4^{-2}x^{-5}y^{-2}z^{4}=\dfrac{1}{16}x^{-5}y^{-2}z^{4}

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write a number you know that is greater than 1 scientific notation.Explain how you know it is greater than 1
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6 0
3 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
Two pumps at a local water facility can only
Ratling [72]

According to the information given, the system of inequalities that models the situation is given by:

  • x + y \geq 18
  • x + y \leq 24
  • 120x + 200y \geq 3000

<h3>System of inequalities:</h3>

For the system, the variables are:

  • x is the number of hours that Pump 1 runs.
  • y is the number of hours that Pump 2 runs.

They will run for at least 18  hours in a day but obviously no more than 24  hours in a day, hence:

x + y \geq 18

x + y \leq 24

Pump 1 can move 120 gallons  per hour while Pump 2 can move 200 gallons  per hour. In total the two pumps must move at  least 3,000 gallons of water per day, hence:

120x + 200y \geq 3000

You can learn more about system of inequalities at brainly.com/question/14361489

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