These are independent events
and probability of drawing red marble is 1/3
and probability of drawing two blue marble is 1/2 ,1/2.
According to the statement
A bag contains 1 white (W), 3 blue (B1, B2, B3), and 2 red (R1, R2) marbles.
And we have to find the probability of tossing a head and drawing a red marble. and probability of drawing two blue marbles if the first marble is not replaced.
here we solve this problem by Probability
So, Probability of drawing red marble = Number of red marble / total number of marbles.
Probability = 2/6
Probability = 1/3.
Then
Probability of drawing blue marbles = number of blue marbles /total marbles
Probability = 3/6
Probability = 1/2.
1st blue marble Probability =1/2
2nd blue marble Probability = 1-(1/2) = 1/2.
These are non dependent events because they do no affect the probability of each others.
So, These are independent events
and probability of drawing red marble is 1/3
and probability of drawing two blue marble is 1/2 ,1/2.
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for an example. If the number is increased by 60% and the denominator is decreased by 20% we get the new fraction being: 
. Since then new one is equal to 1, and the original is equal to 
, we see that this manipulation of the fraction causes an increase of 100%.