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3 years ago

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How can you tell if radicals are like radicals

2 answers:

Harman [31]3 years ago

8 0

Answer and step-by-step explanation:

Like radicals have the same root (square root, cubed root, etc.) and the same expression under the radical sign.

In order to determine if two radicals are like, simplify both and then check both the root and the expression under the radical sign.

valentina_108 [34]3 years ago

6 0

Like radicals are radicals that have the same root number AND radicand (expression under the root).
And there ya have it!

Happy studying.
~Brooke❤️

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Which statement is true about the purpose of trend lines in scatterplots? A trend line must pass through the largest data point.

Eddi Din [679]

Answer:

a trend line can be used to make predictions in real-world situations (the third option)

Explanation:

the first & second options are wrong because it is not a requirement for a trend line to pass through any given data point.

the fourth option is wrong because a trend line shows the general upward/downward trend of the data, and may not necessarily touch all of the data points.

the third option is correct because a trend line helps to roughly estimate the trend (hence the name) of the graph, which allows us to make predictions in real-world situations.

i hope this helps! :D

3 0

3 years ago

Read 2 more answers

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

So

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

3 years ago

Can someone help me with the question? Thanks! <br> xoxo

horrorfan [7]

2. because each x number times 2 plus one is equal to the y range

7 0

3 years ago

What is 9 1/10 as a improper fraction?

Fed [463]

10/1 thats how you will get an improper fraction

8 0

3 years ago

Read 2 more answers

Please solve this with explanation, don’t just give the answer please explain too.

Gemiola [76]

Answer: 30x⁴

Step-by-step explanation:

2x⁴ + (-3x²)² + 10(x²)² + (-3x²)²

2x⁴ + (9x⁴) + 10 (x⁴) + (9x⁴)

2x⁴ + 9x⁴ + 10x⁴ + 9x⁴

2x⁴ + 10x⁴ 9x⁴ + 9x⁴

12x⁴ + 18x⁴

30x⁴

(-x)² = x²

(xᵃ)ᵇ = xᵃᵇ

Hope I helped!

3 0

3 years ago