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2 years ago

Without drawing the graph, find the coordinates of its intersection with the x and y axes.

Mathematics

1 answer:

sesenic [268]2 years ago

7 0

9514 1404 393

Answer:

(0, 2), (2/5, 0)

Step-by-step explanation:

In this slope-intercept form, the y-intercept is the constant in the equation: 2. That is the point of intersection on the y-axis is (0, 2).

When y=0, the value of x is the x-intercept.

0 = -5x +2

5x = 2 . . . . . . add 5x

x = 2/5 . . . . . divide by 5

The point of intersection of the graph with the x-axis is (2/5, 0).

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100

Darina [25.2K]

Answer:

Step-by-step explanation:

given is a function as

$y=\frac{27}{x^3}$

We are to find the area form x=1 to x=t

The curve from x=1 lies in the I quadratnt.

So area above x axis is to be calculated

Area = $\int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )$

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area = $\frac{27}{2} (1-\frac{1}{100^2} )\\= 13.49865$

c) t=10000

area = $\frac{27}{2} (1-\frac{1}{10000^2} )\\= 13.5$

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2 years ago