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3 years ago

Who can solve this question?

Mathematics

1 answer:

Crazy boy [7]3 years ago

8 0

X=20
y=60
z=40
I guess this is true

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The Latin Club charted a bus to travel to and participate in a state competition. The cost for each adult to ride the bus was $2

Tcecarenko [31]

A + s = 17
25a + 15s = 305
on solving for the values of two variables. we get a = 5 and s = 12

3 0

3 years ago

A particle is moving along the curve y= 4sqrt(5x+11) . As the particle passes through the point (5,24) , its -coordinate increas

kupik [55]

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

$y= 4\sqrt{5x+11} .$

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

$\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} } 5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\$

From the question, we have:

(x, y) = (5,24)

Substitute 5 for x and dy / dx = 2

$\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3$

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

Read more about rates of change at:

brainly.com/question/13103052

#SPJ1

8 0

2 years ago

I need help on how I would find the roots to these problems.( show steps please)

katen-ka-za [31]

You need to state the original function(s) to find the additional roots.

3 0

3 years ago

What set of transformations is performed on triangle RST to form triangle R’S’T’?

ra1l [238]

Answer:

D. A translation 2 units down followed by a 270-degree counterclockwise rotation about the origin

Step-by-step explanation:

The given triangle has vertices at R(3,4), S(1,1), and T(5,1)

Translating the the vertices down by 2 units, we apply the rule;

$(x,y)\to (x,y-2)$

$\implies (3,4)\to (3,2)$

$\implies (1,1)\to (1,-1)$

$\implies (5,1)\to (5,-1)$

Rotating the resulting vertices through an angle 270 degrees counterclockwise, we apply the rule:

$(x,y)\to (x,-y)$

$\implies (3,2)\to R'(2,-3)$

$\implies (1,-1)\to S'(-1,-1)$

$\implies (5,-1)\to T'(-1,-5)$

Therefore the correct choice is D.

4 0

3 years ago

Question 2 of 10

Kruka [31]

Answer:

Step-by-step explanation:

Its A

im pretty sure yah!!

7 0

1 year ago