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mote1985 [20]
3 years ago
11

Who can solve this question?

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0
X=20
y=60
z=40
I guess this is true
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A high school band asked a number of students whether they would like blue, gold, or both for the uniforms for the band. The res
Anna35 [415]
Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.

Thus, the total number of students interviewed is 75.

Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.

From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by
\frac{25}{75} = \frac{1}{3}=0.33=33\%

Therefore, a = 33% to the nearest percent.

Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From the Venn, diagram, the number of students that like blue uniform only as 32, thus the relative frequency of the students that like gold but not blue is given by
\frac{32}{75} = 0.427=42.7\%

Therefore, b = 43% to the nearest percent.
7 0
3 years ago
Julie and Eric row their boat (at a constant speed) 55 miles downstream for 5 hours, helped by the
Archy [21]

Answer: C = 3 mph is the rate of the current.

Step-by-step explanation:

Hey there!

<u />

<u>You can use the distance formula (d = rt) to solve this problem.  </u>

Downstream trip: d = 55 miles, t = 5 hours, and r = R + C  

R + C is their rowing speed (R) plus the rate of the current (C).  

Upstream trip: d = 55 miles, t = 11 hours, and r = R - C

R - C is their rowing speed (R) minus the rate of the current (C).  

Downstream: 55 mi. = (R + C)5 hrs. Divide both sides by 5: R + C = 11

Upstream: 55 mi. = (R - C)11 hrs. Divide both sides by 11: R - C = 5

<u>Calculations</u>

R + C = 11 Subtract C from both sides.

R = 11 - C Substitute this into: R - C = 5

(11 - C) - C = 5 Simplify and solve for C

11 - 2C = 5 Add 2C to both sides.

11 = 2C + 5 Subtract 5 from both sides.

6 = 2C Divide both sides by 2

C = 3 mph is the rate of the current.

~I hope I helped you! :)~

5 0
3 years ago
Angela enjoys swimming and often swims at a steady pace to burn calories. At this pace, Angela can swim 1,700 meters in 40 minut
geniusboy [140]
1700÷40= 42.5 

step one: you divide 40 into 1700
step two: you find the closest number that goes into 1700 which is 4 so 40×4= 160
step three: then you subtract 1700 from 160 and you'll get 100
step four: then you'll find the closest number that goes into a 100 and that will be 2 so 40×2=80
step 5: you'll then subtract 100 from 80 and you'll get 20 
step 6: you when then add a decimal and add an extra 0 to 1700 so you will now have 17000 you will bring down the 0 to make 20 into 200 and you will find the closest number that will go into 200 which will be 5 cause 40×5= 200 so you're answer will be 42.5units

7 0
3 years ago
The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me
julia-pushkina [17]

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 200 mg

Sample mean, \bar{x} = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis  for a two tailed test

H_{0}: \mu = 200\\H_A: \mu \neq 200

We use Two-tailed t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799

c) Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

4 0
3 years ago
If the straight line passing through A(-7, -5) and B(-3, x) is parallel to another straight line of slope 2, find the value of x
Ostrovityanka [42]
X=3; you can set up a proportion using the slope equation. So (y[sub2]-y[sub1])/(x[sub2]-x[sub1])=2/1 then plug in the values and simplify. Then cross multiply and solve for x. Rest of work shown in the picture
8 0
3 years ago
Read 2 more answers
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