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ycow [4]
3 years ago
13

Please help!!! ASAP!

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

so what we have to do first is multiply 9*10

which is 90 now we divide by two to get 45

now we multiply 45 by 20 to get

900

Hope This Helps!!!

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Find the a) perimeter and b) area of a rectangle that is 12 inches long and 6.5 inches wide.
Masja [62]
A) 36 inches and b) 78 inches squared
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3 years ago
What is equivalent to 25c+15
aniked [119]

The Answer is: 5 (5c+3)

Step-by-step explanation:

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3 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
LenKa [72]
We only need to find the heights of the 2 points on the flagpole and then subtract them. We have that AC and DC are related by the following trigonometric number: tan60=AC/DC. This is because ADC is a right triangle and AC is the opposite leg of the angle we know, while DC is the adjacent leg.
tan60= \sqrt{3} =AC/5 \sqrt{3} \\ AC=5  \sqrt{3} * \sqrt{3} =5*3=15.

Thus, we have calculated AC. The same remarks apply to the triangle BCD; However, now we get that tan30=BC/DC.
tan60= 1/\sqrt{3} =BC/5 \sqrt{3} \\ BC=5  \sqrt{3} / \sqrt{3} =5.


Hence, the height of point B is 5 feet, while the height of point A is 15 feet. Their distance is 10 feet.


5 0
3 years ago
Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

6 0
3 years ago
Frank invested $1000 in an account with a 6% interest rate compounded annually. How much is the account after 3 years?
Wewaii [24]
I belive c is the corect awnser

4 0
3 years ago
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