3 years ago

Find the missing angle measures

Mathematics

1 answer:

padilas [110]3 years ago

4 0

Answer:

72°

44°

Step-by-step explanation:

a circle=116° those are the measures

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I think the answer is 745

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In triangle JKL, tan(b°) = 3/4 and cos(b°) =4/5. If triangle JKL is dilated by a scale factor of 1/2, what is sin(b°)?

zysi [14]

Answer:

$\sin (b^\circ)=\dfrac{3}{5}$ .

Step-by-step explanation:

It is given that,

$\tan (b^\circ)=\dfrac{3}{4}$

$\cos (b^\circ)=\dfrac{4}{5}$

If a figure is dilated, then the image is similar to the figure. It means the corresponding angles of figure and image are congruent.

So, the value of sin(b°) after dilation is equal to the value of sin(b°) before dilation.

We know that,

$\dfrac{\sin \theta}{\cos \theta}=\tan \theta$

$\dfrac{\sin (b^\circ)}{\cos (b^\circ)}=\tan (b^\circ)$

$\sin (b^\circ)=\tan (b^\circ)\times \cos (b^\circ)$

$\sin (b^\circ)=\dfrac{3}{4}\times \dfrac{4}{5}$

$\sin (b^\circ)=\dfrac{3}{5}$

Therefore, $\sin (b^\circ)=\dfrac{3}{5}$ .

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