It won 12 times. 18 divided by 3 is 6, add six to six and you get 12 :)
Answer:
No solution.
Step-by-step explanation:
(1/12)^-2b * 12^(-2b + 2) = 12
1/12 is basically the same thing as 12^-1.
12^(-1 * -2b) * 12^(-2b + 2) = 12
12^2b * 12^(-2b + 2) = 12
12^(2b - 2b + 2) = 12
12^2 = 12
Since the answers don't match up, the answer will be no solution.
Hope this helps!
6.45 + 19.82 = c) 26.27
64.5 + 1.983 = a) 66.483
6.45 - 1.983 = b) 4.467
64.5 - 19.83 = d) 44.67
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.
<h3>What is an area bounded by the curve?</h3>
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0
The intersection points will be
y₁ = y₂
4 - 4x² = 0
x = ±1
Then the area bounded by the curves will be
![\rm Area = \int _{-1}^1 (y_1- y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \](https://tex.z-dn.net/?f=%5Crm%20Area%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%28y_1-%20%20y_2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%284%20-%204x%5E2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cleft%20%5B%204x%20%20-%20%5Cdfrac%7B4x%5E3%7D%7B3%7D%20%5Cright%20%5D_%7B-1%7D%5E1%5C%5C%5C%5CArea%20%3D%204%20%5Cleft%20%28%201%20%2B%201%20%5Cright%20%29%20-%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cleft%20%28%201%5E3%20-%20%28-1%29%5E3%20%5Cright%20%29%5C%5C%5C%5CArea%20%3D%208%20-%20%5Cdfrac%7B8%7D%7B3%7D%5C%5C%5C%5CArea%20%3D%20%5Cdfrac%7B16%7D%7B3%7D%20%3D%205.333%20%5C)
More about the area bounded by the curve link is given below.
brainly.com/question/24563834
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