How many different teams of 11 players can be chosen from a soccer team of 15?
2 answers:
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Answer:
The price of adult's ticket is $ 17.73 And
The price of children's ticket is $ 13.85
Step-by-step explanation:
Given as :
The Prices for adult ticket and child ticket in the city zoo is different
Let the price for adult's ticket = $ A
And The price for child's ticket = $ C
Now, according to question :
3 A + 2 C = $ 80.89 And
2 A + 3 C = $ 77.01
Now solve the both equation
So, 2 × (3 A + 2 C) = 2 × $ 80.89 And
3 × (2 A + 3 C) = 3 × $ 77.01
I.e
6 A + 4 C = $ 161.78 And
6 A + 9 C = $ 231.03
Now, ( 6 A + 9 C ) - ( 6 A + 4 C ) = $ 231.03 - $ 161.78
Or, 5 C = $ 69.25
Or, C = $ 13.85
And Put the value of C in above any eq
6 A + 4 × ($ 13.85) = $ 161.78
Or, 6 A = $ 161.78 - $ 55.4
Or, 6 A = $ 106.38
∴ A =
Or, A = $ 17.73
Hence The price of adult's ticket is $ 17.73 And
The price of children's ticket is $ 13.85 Answer
Answer:
0.01083 or 1.083%
Step-by-step explanation:
This problem can be modeled as a binomial probability model with probability of success p = 0.56.
The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:
The probability is 0.01083 or 1.083%.