1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madam [21]
3 years ago
11

Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r

un of resistors of 1,000 ohms each. Use Exhibit 10.13. To set up the machine and to create a control chart to be used throughout the run, 15 samples were taken with four resistors in each sample. The complete list of samples and their measured values are as follows: Use three-sigma control limits. SAMPLE NUMBER READINGS (IN OHMS) 1 1027 994 977 994 2 975 1013 999 1017 3 988 1016 974 997 4 998 1024 1006 1010 5 990 1012 990 1000 6 1016 998 1001 1030 7 1000 983 979 971 8 973 982 975 1030 9 992 1028 991 998 10 997 1026 972 1021 11 990 1021 1028 992 12 1021 998 996 970 13 1027 993 996 996 14 1022 981 1014 983 15 977 993 986 983 a. Calculate the mean and range for the above samples.
Mathematics
1 answer:
Anettt [7]3 years ago
8 0

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

\bar x = \frac{\sum x}{n} ---- mean

Where:

n = 4 ---- number of rows

R = Highest - Lowest --- range

So, we have:

Sample 1

\bar x_1 = \frac{1027+ 994 +977 +994 }{4}

\bar x_1 = 998

R_1 = 1027- 994

R_1 = 33

Sample 2

\bar x_2 = \frac{975 +1013 +999 +1017}{4}

\bar x_2 = 1001

R_2 =  1017 - 975

R_2 = 42

Sample 3

\bar x_3 = \frac{988 +1016 +974 +997}{4}

\bar x_3 = 993.75

R_3 = 1016-974

R_3 = 42

Sample 4

\bar x_4 = \frac{998 +1024 +1006 +1010}{4}

\bar x_4 = 1009.5

R_4 = 1024 -998

R_4 = 26

Sample 5

\bar x_5 = \frac{990 +1012 +990 +1000}{4}

\bar x_5 = 998

R_5 = 1012 -990

R_5 = 22

Sample 6

\bar x_6= \frac{1016 + 998 +1001 +1030}{4}

\bar x_6= 1011.25

R_6= 1030-998

R_6= 32

Sample 7

\bar x_7 = \frac{1000 +983 +979 +971}{4}

\bar x_7 = 983.25

R_7 = 1000-971

R_7 = 29

Sample 8

\bar x_8 = \frac{973 +982 +975 +1030}{4}

\bar x_8 = 990

R_8 = 1030-973

R_8 = 57

Sample 9

\bar x_9 = \frac{992 +1028 +991 +998}{4}

\bar x_9 = 1002.25

R_9 = 1028 -991

R_9 = 37

Sample 10

\bar x_{10} = \frac{997 +1026 +972 +1021}{4}

\bar x_{10} = 1004

R_{10} = 1026 -972

R_{10} = 54

Sample 11

\bar x_{11} = \frac{990 +1021 +1028 +992}{4}

\bar x_{11} = 1007.75

R_{11} = 1028 -990

R_{11} = 38

Sample 12

\bar x_{12} = \frac{1021 +998 +996 +970}{4}

\bar x_{12} = 996.25

R_{12} = 1021 -970

R_{12} = 51

Sample 13

\bar x_{13} = \frac{1027 +993 +996 +996}{4}

\bar x_{13} = 1003

R_{13} =1027 -993

R_{13} =34

Sample 14

\bar x_{14} = \frac{1022 +981 +1014 +983}{4}

\bar x_{14} = 1000

R_{14} = 1022 -981

R_{14} = 41

Sample 15

\bar x_{15} = \frac{977 +993 +986 +983}{4}

\bar x_{15} = 984.75

R_{15} = 993-977

R_{15} = 16

You might be interested in
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
PLZZ HELP I REALLY NEED TO PASS<br><br> Using similarity solve for x. Show all work.
Ede4ka [16]
The answer would be the square root of 25 times 9 im pretty sure its been while and it would be 25*9=225 square root of 225 is 15
5 0
3 years ago
Lonnie plans to join the gym. He must pay a $35 membership fee. He will
SVETLANKA909090 [29]

Answer: 5

Step-by-step explanation:

6 0
3 years ago
What is the equation for the line through the origin and (3, 4)
inn [45]

Answer:

pls amke it more clear pls just pls

Step-by-step explanation:

3 0
3 years ago
A package weighs P pounds P being a whole number. to ship this package by express costs one dollar and sixty five cents for the
deff fn [24]
Whole package weighs 20pounds

1.65 = 5pounds
0.12 = extra pound

3.45 - 1.65 = 1.80 : 0.12 = 15pounds
Adding up 15pounds and the first 5 pounds equal 20 pounds
5 0
3 years ago
Other questions:
  • In which​ quadrant, if​ any, is the point (0, - 4.5) right parenthesis(0,−4.5) ​located?
    15·2 answers
  • A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. find the value that is +3 standard devi
    12·2 answers
  • 9.74 x 1021_______2.1 x 1022 help me please with this? thanks to whoever does..............​
    9·1 answer
  • Select the correct answer from each drop-down menu.
    12·2 answers
  • PLEASE HELP THIS IS DUE TODAYYYY
    14·1 answer
  • What is the decimal multiplier to decrease by 39%
    5·1 answer
  • 1/3x + y = 6<br> -x - 2y = -9 <br><br> Using elimination
    12·1 answer
  • Based on △GHI below, which of the following inequalities is true?
    7·1 answer
  • Tell me what is wrong with this.<br> _____<br> / \<br> | |<br> |______|<br> | | | |<br> | | | |
    6·1 answer
  • Divide. Enter the quotient in simplest form. 7 10 ÷ 2 5 =
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!