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lara [203]
3 years ago
9

The following table shows how much Dave gave each of his kids for allowance last month Find the median allowance

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

7

Step-by-step explanation:

1. arrange the numbers from smallest to biggest

2. cross on each side until you reach a middle number

3. if there's two digits , add them both and divide by two

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Now round 3.152 to the nearest one.
Alika [10]
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8 0
3 years ago
Adam was going to sell all of his stamp collection to buy a video game. After selling half of them he changed his mind and did n
Roman55 [17]
He would have 21 before he bought the 10 stamp because 31-10=21
6 0
4 years ago
Can someone help please
finlep [7]

Answer:

x=7 y=3

Step-by-step explanation:

-x+6y=11

2x-3y=5

-2x+12y=22

2x-3y=5

Add both equations

-2x+2x-3y+12=22+5

9y=27

y=3

plug y back in

-x+18=11

-x=-7

x=7

3 0
2 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
3 years ago
Help me with myn math class good luck
WINSTONCH [101]
Provide me the questions you need help with and ill try to further assist you!
7 0
3 years ago
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