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3 years ago

The following table shows how much Dave gave each of his kids for allowance last month Find the median allowance

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Answer:

Step-by-step explanation:

1. arrange the numbers from smallest to biggest

2. cross on each side until you reach a middle number

3. if there's two digits , add them both and divide by two

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Now round 3.152 to the nearest one.

Alika [10]

3

Mark brainliest please

Hope this helps you

8 0

3 years ago

Adam was going to sell all of his stamp collection to buy a video game. After selling half of them he changed his mind and did n

Roman55 [17]

He would have 21 before he bought the 10 stamp because 31-10=21

6 0

4 years ago

Can someone help please

finlep [7]

Answer:

x=7 y=3

Step-by-step explanation:

-x+6y=11

2x-3y=5

-2x+12y=22

2x-3y=5

Add both equations

-2x+2x-3y+12=22+5

9y=27

y=3

plug y back in

-x+18=11

-x=-7

x=7

3 0

2 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

Help me with myn math class good luck

WINSTONCH [101]

Provide me the questions you need help with and ill try to further assist you!

7 0

3 years ago