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2 years ago

Help and explain pls and thankyouuu

Mathematics

1 answer:

netineya [11]2 years ago

6 0

Answer: (1, 8)

Step-by-step explanation:

<u>Substitute y = 3x + 5 into the equation 2x + 3y = 26:</u>

2x + 3(3x + 5) = 26

2x + 9x + 15 = 26

11x = 26 - 15

11x = 11

x = 1

<u>Substitute the value of x into the equation y = 3x + 5:</u>

y = 3(1) + 5 = 3 + 5 = 8

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A piston is seated at the top of a cylindrical chamber with radius 3 cm when it starts moving into the chamber at a constant spe

dlinn [17]

Answer:

1. V = πr²h

2. dv/dt = πr²dh/dt

3. dv/dt = 113.04

Step-by-step explanation:

We have these information

Radius R = 3cm

Height = h

Volume = V

We have been given dh/dt = 4cm

An equation relating V, r, h

Volume of cylinder = πr²h

The related rates equation

dv/dt = πr²dh/dt

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3. Continuing from number 2 above, we have

dv/dt = π3²dh/dt

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3 years ago

If f(x)=x and g(x)=2, what is (f o g)(x)?

IgorC [24]

Answer:

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Step-by-step explanation:

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3 years ago

Which of the following is a trinomial?

Sedaia [141]

Answer:

$A) c^2 + c + 6$

Step-by-step explanation:

We have been given four choices out of which we need to select the choice which is trinomial.

Trinomial means polynomial having three terms.

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3 years ago

54 + 81 = 9(6 +_) I need the help to answer my question

Otrada [13]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago