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a_sh-v [17]
3 years ago
5

The vertices of a figure are given. Rotate the fig

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ) , then

A (2, - 2 ) → A' (2, 2 )

B (4, - 1 ) → B' (1, 4 )

C (4, - 3 ) → C' (3, 4 )

D (2, - 4 ) → D' (4, 2 )

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Which of the following best represents the relationship between angles A and B?
Readme [11.4K]

Answer:

A = B

Step-by-step explanation:

This is because they are alternate exterior angles and they equal the same thing.

4 0
3 years ago
Read 2 more answers
Hakim invests $700 in a bank that pays 5% simple interest annually. After one year he uses the money in his account to buy a com
Keith_Richards [23]
The answer is $22.00
4 0
3 years ago
Bonsoir vous pouvez m’aider alors : A la masse x (en g) d’un objet suspendu , on associe la longueur (en mm) d’un ressort . Cett
natita [175]

Answer:

50 g = 95mm

60 g = 98 mm

0 g = 98/60 = 1.63 mm Step-by-step                                                      explanation:hope this help y'all

8 0
3 years ago
On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d
Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

                         X~ N ( 67.2 , 4.6^2 )

Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

6 0
3 years ago
Find distance (4,7) (-4,-3)​
AURORKA [14]

∆x = (4--4)=8

∆y = (7--3)= 10

Step-by-step explanation:

distance is given by;

d² = (∆y)²+ (∆x)²

d = √((∆y)²+ (∆x)²)

d = √((4+4)² + (7+3)²)

d = √((8²) + (10²))

d = √(64+100)

d = √164

<em><u>d =12.806 units</u></em>

7 0
3 years ago
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