Y’all plz- help this is so hard giving brainlest ;)
2 answers:
Answer:
<em>Answer: B.</em>
Step-by-step explanation:
<u>Quadrants in the Coordinate Plane</u>
The coordinate plane is divided into 4 quadrants named I, II, III, and IV as shown in the image attached below.
The first quadrant (I) has the x positive and the y positive
The second quadrant (II) has the x negative and the y positive
The third quadrant (III) has the x negative and the y negative
The fourth quadrant (IV) has the x positive and the y negative.
A point located in quadrant III must have both coordinates negative. This only corresponds to choice B where both components are negative.
Answer: B.
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We factor the denominators
Factor x^2 - 16
x^2 - 4^2
We use a^2 - b^2 = (a+b)(a-b)
so x^2 - 4^2 = (x+4)(x-4)
Replace it in the given equation
Excluded values are the values that makes the denominator 0
we have (x-4) and (x+4) in the denominator
We set the denominator =0 and solve for x
x-4 =0
Add 4 on both sides
x= 4
x+4=0
subtract 4 onboth side
so x= -4
Excluded values are x=-4 and x=4