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2 years ago

5

Please please help please please ASAP please I'm begging you please I have 10 minutes please y'all help please any ACE that can

help please

2 answers:

Finger [1]2 years ago

8 0

Answer:

RQ

Step-by-step explanation:

ML:RQ = MN:RS = LN:QS (corr side, similar triangles)

ycow [4]2 years ago

6 0

It’s RQ hope it’s help have a nice day

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What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 9x?

saveliy_v [14]

Answer: -3/2

Step-by-step explanation:

The axis of symmetry, and thus the x-coordinate of the vertex, is given by $x=-\frac{b}{2a}$

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1 year ago

A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi

lisov135 [29]

<h2>Answer:</h2>

$\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle $11\pi /2=165^{\circ}$ , therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry:

$\overline{BC}=\overline{AB}sin(75^{\circ})=50sin(75^{\circ})=\frac{25}{2}(\sqrt{6}+\sqrt{2})$

Finally, the height is:

$H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+15+50 \\ \\ \boxed{H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

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3 years ago

Can u plzz find me a length of adjacent

timofeeve [1]

Answer:

There is no answer

My Logic:

The picture does not specify the degree of angle for each corner, nor can i understand what the random "a" is. also the side all the way to the left has an un-readable number.

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2 years ago