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Serggg [28]
3 years ago
9

Which equation does not represent a function? Why? A) y = x2; There are two outputs for each input. B) y2 = 4x; There are two ou

tputs for each input. C) y = x; The output value is the same as the input value. D) y = −x; The output value is the opposite of the input value.
Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

B) y² = 4x; There are two outputs for each input

Step-by-step explanation:

For an equation to be called a function, the input values for x must only result in a single output for y.

Based on this definition if a function, the functions y = x², y = -x and y = x are all functions because for any value of x imputed in them, we can only get one equivalent value of y.

The only exception is the function y²= 4x

For this function, for any value of x, there will be more than one output for y. Take x = 1 for example

y² = 4(1)

y² = 4

y = ±√4

y = ±2

This shows that y = 2 and -2

Also if x = 4

y² = 4(4)

y² = 16

y = ±√16

y = ±4

y = 4 and -4

No matter the value of x imputed, the output value y will always be two (a positive and a negative value)

Hence, option B is correct.

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A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

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Answer:

B. \frac{d + 13}{d + 4}

Hope this Helps :)

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Step-by-step explanation:

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