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Serggg [28]
4 years ago
9

Which equation does not represent a function? Why? A) y = x2; There are two outputs for each input. B) y2 = 4x; There are two ou

tputs for each input. C) y = x; The output value is the same as the input value. D) y = −x; The output value is the opposite of the input value.
Mathematics
1 answer:
natita [175]4 years ago
3 0

Answer:

B) y² = 4x; There are two outputs for each input

Step-by-step explanation:

For an equation to be called a function, the input values for x must only result in a single output for y.

Based on this definition if a function, the functions y = x², y = -x and y = x are all functions because for any value of x imputed in them, we can only get one equivalent value of y.

The only exception is the function y²= 4x

For this function, for any value of x, there will be more than one output for y. Take x = 1 for example

y² = 4(1)

y² = 4

y = ±√4

y = ±2

This shows that y = 2 and -2

Also if x = 4

y² = 4(4)

y² = 16

y = ±√16

y = ±4

y = 4 and -4

No matter the value of x imputed, the output value y will always be two (a positive and a negative value)

Hence, option B is correct.

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Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

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The biggest possible volume of the cylinder will be 2089.497\hspace{1mm}\text{cm}^3.

<h3>What will be the diameter and height of the cylinder obtained from a cube and what are the formulas for the diagonal of a cube and the volume of a cylinder?</h3>
  • If a cylinder with the biggest possible volume is cut inside the cube, the height of the cylinder and the diameter of the cylinder will be equal to the side length of the cube.
  • For example, consider the following figure in which the cylinder is cut inside of the cube and since the side length of the cube is x, the diameter and the height of the cylinder are also x
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