Answer:
- A. Figure ABCD is similar to figure A′B′C′D′
Step-by-step explanation:
Refer to attached graph
<u>Statements </u>
Figure ABCD is similar to figure A′B′C′D′.
- True. Similar sides and congruent angles.
Figure ABCD is bigger than figure A′B′C′D′.
- False. They have same area.
The measure of angle D is equal to the measure of angle A′.
The measure of angle D is equal to the measure of angle B′.
-5y=12-3x (subtract 3x from both sides)
y = - 12-3x/5 (divide both sides by -5)
y = - 3(4-x)/5 (common term is 3)
Take the angle then multiple them by what ever needs to be, then finish it. and sorry not in geometry abd i am not good with angles.
e. 72.
Let x be the measurement of the 3rd side.
x should be greater that the difference of 2 sides
x should be less than the sum of 2 sides
20 - 15 < x < 20 + 15
5 < x < 35
We can assume that x = 35 the maximum measurement of the 3rd side.
Perimeter = 20 + 15 + 35 = 70. Maximum perimeter.
Among the choices, 72 is beyond the maximum, so it is not a possible perimeter of the triangle.
Pull an x from the first two terms
x(x^3 + y^3) + (x^3 + y^3) Now x^3 + y^3 is a common factor.
(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors
(x^3 + y^3) = (x + y)(x^2 - xy + y^2)
Which means you could write original polynomial as
(x + y)(x^2 - xy + y^2)(x + 1)
Part B
You factored the x out of xy^3 so that you would have a common factor (x^3 + y^3) to pull out as a common factor for the whole polynomial.
