Reflection over the y axis Then a translation of 2 units down
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
y=4x+11
Step-by-step explanation:
multiply 4 into the parentheses to get y-3=4x+8 then invert -3 so add three to both sides to get rid of it so instead of +8 its +11 so now its y=4x+11 and slope intercept is y=mx+b, so 4 is m, slope, and 11 is b, the y intercept i hope that helps
I think the answer is d or b if im wrong sorry hope this helped tho :p
I think D and E. The point slope formula is y-y₁=m(x-x₁).
