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Sidana [21]
3 years ago
14

On a sunny day, a tree casts a shadow that is 146 feet long. At the same time, a person who is 5.6

Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0
Let X = tree height.

X/146 = 5.6/11.2
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Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18
enot [183]

Answer:

2y - 3x = -15

Step-by-step explanation:

Slope of the line 4x + 6y = 1 is as shown below;

Rewrite in slope intercept form;

6y = -4x+1

y = -4x/6 + 1/6

y = -2x/3 + 1/6

mx = -2/3x

m = -2/3

The slope of the line perpendicular M = -1/(-2/3)

M = 3/2

Get the x and y intercept of 2x+3y = 18

x intercept occurs when y  = 0

2x + 0 = 18

x= 18/2

x = 9

y intercept occurs when x  = 0

0 + 3y = 18

3y= 18

y = 18/3

y = 6

The line passes through the point (9,6)

Write the equation in point slope form

y - y0 = m(x-x0)

y - 6  = 3/2(x-9)

2(y-6) = 3(x-9)

2y - 12 = 3x - 27

2y - 3x = -27 + 12

2y - 3x = -15

This gives the required equation

8 0
3 years ago
NEED HELP, ASAP! !!! 2 QUESTIONS.
Maksim231197 [3]

Answer:

1.we know the perimeter of the triangle=x-3+x+6+x=3x+3

so,answer is (b)3x+3

2.area of the triangle=1/2*b*h

=1/2*x+2*2x+6=x+2*2x+6/2=2x^2+6x+4x+12/2=2x^2+10x+12/2=2(x^2+5x+6)/2=x^2+5x+6

so,answer is(b)x^2+5x+6

8 0
3 years ago
Graph ABCD if A(1, 4), B(6, 6), C(4, 1), and D(−1, −1). Is ABCD a rhombus? Show how you know.
stich3 [128]

C4,1 because I solved it and it showed me

6 0
3 years ago
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
2 years ago
Evaluate 8j - k+14 when j=0.25 and k=1
Naddik [55]
8(0.25)-1+14
2-1+14
1+14
15
4 0
3 years ago
Read 2 more answers
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