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Lelu [443]
3 years ago
8

A recipe calls for 1 /3 cup of sugar 2 cups of flour. How many cups of flour do you need to add 3 cups of sugar?

Mathematics
2 answers:
salantis [7]3 years ago
6 0
18 cups of flour because each cup is 6 cups of flower (1/3 x 3 x 2) and you need 3 cups so 6 x 3 is 18
muminat3 years ago
3 0

Answer:

With a video tutorial and in-depth explanations, learn how to properly measure baking ingredients and why measuring is so crucial in baking.

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You choose two different songs on a music playlist at random. Out of 80 songs on the playlist, 36 are hip hop songs. The first s
dexar [7]

Answer:

35/79

Step-by-step explanation:

Assuming you can't choose the same song a second time, the probability is 35/79.

If you can choose the same song, the probability is 36/80, which reduces to 9/20.

7 0
4 years ago
A linear regression was conducted on the number of cigarettes a person smokes in a day versus the number of times they cough in
makvit [3.9K]

Answer:

a) response variable

Step-by-step explanation:

The response variable is the variable that depends on other variables such as the independent or explanatory variable, it is the variable that is being tested. The response variable is also called the dependent variable.

In linear regression, the y variable is referred to as the response variable while the x variable is referred to as the explanatory or independent variable.

In this case the y variable is "the number of times they cough in a day" and this variation depends on the x variable "number of cigarettes a person smokes in a day".

8 0
3 years ago
Which of these graphs represents a function?
Likurg_2 [28]
Do you have any graphs because that would be more clear
7 0
3 years ago
Read 2 more answers
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
3 years ago
Find FJ plsssssssssssss
Whitepunk [10]

Answer:

the value of FJ would end up being 10

7 0
3 years ago
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