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JulijaS [17]
3 years ago
7

30 Yuri has two plum trees, A and B. in his garden

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

42kg

Step-by-step explanation:

We are given the amount of plums produced from Tree A. We simply need to <u>find the amount produced by Tree B</u> and <u>add</u> the two numbers up.

Step 1:

Tree B produces 10% more than Tree A, which produces 20kg of plums:

B=\frac{110}{100} *\frac{20}{1} \\\\B=\frac{110}{5}=\\\\B=22

Ok! Tree B produces 22kg of plums. Let us find the total amount of plums Yuri gets from both trees.

Step 2:

Total=A+B\\\\Total=20+22\\\\Total=42

<u>Yuri gets 42 kg of plums from the trees.</u>

<u />

<em>I hope this helps! Let me know if you have any questions :)</em>

<em />

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Help !!!!!!!!!!!!!!!! plz
vovikov84 [41]

Answer:

5 > n + 10

8 x 7 < n

n/3 + 1

6 x 8 - 10 < n

n - 1 x n

n x -n + 7

4 0
3 years ago
Which number best represents the location of the point on the line?
MrRissso [65]

Answer:

x=0

Step-by-step explanation:

all falls or passes through the x eventually

7 0
3 years ago
PLEASE HELP, THIS IS DUE ALREADY AND I AM IN A HUGE HURRY
Fed [463]

Solution:

<u>Note that:</u>

  • Given equation: y = 8x

<u>Let's substitute x as 2 to find out y.</u>

  • y = 8x
  • => y = 8(2)
  • => y = 16

<u>Let's substitute x as 4 to find out y.</u>

  • y = 8x
  • => y = 8(4)
  • => y = 32

<u>Final answer:</u>

  • When x = 2, y = 16
  • When x = 4, y = 32

Option B is correct.

7 0
2 years ago
Find the coordinates of the point of intersection of all parabolas that have equation y=x2+px +q with p+q=2020. The point of int
ioda

Answer:

(1,2021)

Step-by-step explanation:

P and q can vary subject to their sum being 2020.

Consider one parabola with p1 and q1 and another with p2 and q2.

y1=(x1)^2+(p1)(x1)+(q1)

y1=(x2)^2+(p2)(x2)+(q2)

At their intersection, the x and y coordinates are the same.

y1=y2=y

x1=x2=x

x^2+(p1)x+(q1)=x^2+(p2)x+(q2)

Solve for x

x(p1-p2)=q2-q1

x=(q2-q1)/(p1-p2)

Use the constraint that p+q=2020 to eliminate p1 and p2.

p1=2020-q1

p2=2020-q2

x=(q2-q1)/(2020-q1-2020+q2)

x=(q2-q1)/(q2-q1)

x=1

Substitute in the equation for y.

y=1^2+p(1)+q

y=2021

3 0
3 years ago
How do I graph this?
Harrizon [31]

Answer:

So, in order to solve this, you need to know slope. Slope is equal to rise (up/down) over run (left/right). The number at the end, which in this case is 2, is the y-intercept. So, first, graph a point on the y-axis, which is 2. Next, you can place any other point on the line, as long as it follows your slope, which is 3/5. If you need a better explanation, just graph (0, 2) on the y-axis and also graph the point (3, 5).

Have a good one,

Philip

BRAINLIEST IS ALWAYS APPRECIATED! <3

4 0
3 years ago
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