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arlik [135]
3 years ago
12

Which statement is an example of the transitive property of congruence?

Mathematics
2 answers:
Westkost [7]3 years ago
5 0
An example of the transitive property of congruence is <span>D. If and , then .</span>
AlexFokin [52]3 years ago
4 0

Answer:

D. If  and , then is an example of transitive property of congruence.

Step-by-step explanation:

Transitive property of congruenc: If one segment is congruent to second segment and second is congruent to third segment then the segment one is congruent to third segment.

For example: If \overline{ AB} \cong  \overline {BC}

and \overline{BC} \cong \overline{CD}

Then \overline{AB} \cong  \overline {CD}

Therefore we can see in angles

If \angle ABC \cong \angle BCA

And \angle BCA \cong \angle CAB

Then \angle ABC\cong \angle CAB

Therefore, the statement of transitive property written as

If and, then

Hence, If and,  then is an example of the transitive property of congruence.

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Emily and Holly took a road trip together. Emily drove at an average of 45 miles per hour for the first 3/7 of the total distanc
Elan Coil [88]
Emily drove 3/7 of the total distance and holly drove the rest which explains that holly drove 4/7 of the whole distance.

if 4 parts of the distance equals 24 miles, then 1 part would be 24/4 is 6.
since emily drove 3 parts of the whole distance, it is 6 × 3 = 18 miles.

travelling time of emily = 18/45 = 0.4 hr
travelling time of holly = 24/54 = 0.4 hr
--> total traveling time = 0.8 hr

i hope it is right
3 0
3 years ago
Which statement is true of triangles P and Q? Triangle P has side lengths of 6, 8, 10 and angle measures of 53.1 degrees, 90 deg
Andre45 [30]

Answer:

C. They are similar because their corresponding angles are congruent and their corresponding side lengths are proportional.

3 0
4 years ago
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Find the fifth roots of 32(cos 280° + i sin 280°)
shusha [124]

Answer:

The fifth root is 2[cos(56°) + i sin(56°)]

Step-by-step explanation:

* To solve this problem we must revise De Moiver's rule

- In the complex number with polar form

∵ z = r(cosФ + i sinФ)

∴ z^n = r^n(cos(nФ) + i sin(nФ))

* In the problem

- The fifth root means z^(1/5)

- We can put 32 as a form a^n

∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5

∴ z = 2^5[cos(280°) + i sin(280°)]

* Lets find z^(1/5)

*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)

*(2^{5})^{\frac{1}{5}}=2^{5.\frac{1}{5}}=2

∴ z^(1/5) = 2[cos(56) + i sin(56)]

* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]

 

4 0
3 years ago
What is the approximate area of the shaded sector in the circle shown below
Reil [10]

Answer:

Correct option is B.

Step-by-step explanation:

Given the radius of circle and the angle in sector we have to find the area of shaded region i.e minor sector.

                   

                   

∴ Area of sector is

Correct option is B.

3 0
3 years ago
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