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3 years ago

K(x) = -2x + 6 Find k(0) Please help!

Mathematics

1 answer:

sasho [114]3 years ago

4 0

Answer:

k(0) = 6

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

k(x) = -2x + 6

k(0) is x = 0

Step 2: Evaluate

Substitute: k(0) = -2(0) + 6
Multiply: k(0) = 0 + 6
Add: k(0) = 6

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Answer:

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Step-by-step explanation:

180(n)-360=interior angle sum

180(11)-360=1620

n = number of sides

You also can divide it by 11 to know each interior angle.

1620/11=~147.27

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3 years ago

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3 years ago

Point B has coordinates (1,2). The x-coordinate of point A is -8. The distance between point A and point B is 15 units. What

Xelga [282]

Answer:

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

$l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}}$ (1)

Where:

$l_{AB}$ - Length of the line segment AB.

$x_{A}, x_{B}$ - x-coordinates of points A and B.

$y_{A}, y_{B}$ - y-coordinates of points A and B.

If we know that $l_{AB} = 15$ , $x_{A} = -8$ , $x_{B} = 1$ and $y_{B} = 2$ , then the possible coordinates of point A is:

$\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15$

$81 + (2-y_{A})^{2} = 225$

$(2-y_{A})^{2} = 144$

$2-y_{A} = \pm 12$

There are two possible solutions:

1) $2-y_{A} = -12$

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2) $2 - y_{A} = 12$

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3 years ago

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son4ous [18]

one angle is 3x-3

another angle is 6(x-10)

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Vertically opposite angles are always equal

So we equation both the angles and solve for x

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3x - 3 = 6x - 60

Subtract 6x from both sides

-3x - 3 = -60

Add 3 on both sides

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Divide by 3

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3 years ago

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Answer:

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2 years ago

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