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Anni [7]
3 years ago
15

Average of 5, 25 and y =30 which is true? y<25, 25

Mathematics
1 answer:
sweet [91]3 years ago
4 0
I can’t see the other answers, but f they are all >, <, =, then your answer is y>25
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Enter the correct number<br> 1/5 of 35 bottles of water =
Alex777 [14]

Answer:

7

Step-by-step explanation:

you divide the 35 by 1/5 to get 7 bottles of water

7 0
2 years ago
Read 2 more answers
One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers
Reptile [31]
Let, 
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)

\frac{1}{x} + \frac{1}{y}= \frac{45}{4}...................................equation (2)

Taking equation (2)
\frac{1}{x} + \frac{1}{y}= \frac{45}{4}

Substituting the value of "x" from equation (1), we get,

\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}

\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}

\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}

\frac{1+4}{4y} = \frac{45}{4}

\frac{5}{4y} = \frac{45}{4}

Cross multiplying, we get,

5*4 = 45*4y

20 = 180y
<u />
\frac{20}{180}  = y

\frac{1}{9}  = y

y =  \frac{1}{9}

Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

x = 4( \frac{1}{9} )

x= \frac{4}{9}

So, the numbers are \frac{1}{9} and \frac{4}{9}

7 0
3 years ago
Read 2 more answers
The point y (-3,-1) is rotates 270 degrees. Please help
uranmaximum [27]

it is going to be c cause i know cause my kid does it

6 0
3 years ago
Write this expression using exponents
alexdok [17]

Answer:

4p^{2} or 4p^2

Step-by-step explanation:

Combine like terms:

4 x 4 and p x p

4^2 and p^2

4p^2

4 0
3 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

7 0
3 years ago
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