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3 years ago

Calculate the value of A in the statement

Mathematics

1 answer:

tigry1 [53]3 years ago

4 0

please edit your question man

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The points in the table lie on a line. Find the slope of the line.

wolverine [178]

Answer

Y=5x+2

I’m not sure but I think that’s the answer

8 0

3 years ago

Select the correct answer.

nordsb [41]

Answer:

A. The graph is a line that goes through the points (9,0) and (0,6).

Step-by-step explanation:

Given

$4x + 6y = 36$

Required

Select the true options

$(a)\ (9,0)\ and\ (0,6)$

This implies that"

$(x_1,y_1)= (9,0)$

$(x_2,y_2)= (0,6)$

So, we have: $(x_1,y_1)= (9,0)$

$4x + 6y = 36$

$4 * 9 + 6 * 0 = 36 + 0 = 36$

So, we have: $(x_2,y_2)= (0,6)$

$4 * 0 + 6 * 6 = 0 + 36 = 36$

<em>Hence (a) is true.</em>

3 0

3 years ago

What is the domain of {(1,0),(-5,7),(-4,-7),(-7,-4)}

olasank [31]

D(1,-5,-4,-7) R(0,7,-7,-4) Domain are your x values and range is your y values

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%204x-15%3D3" id="TexFormula1" title="\sf 4x-15=3" alt="\sf 4x-15=3" align="absmiddle" cl

AnnZ [28]

Answer:

$4x - 15 = 3 \\ 4x = 3 + 15 \\ 4x = 18 \\ x = \frac{18}{4} \\ x = \frac{9}{2} \\ x = 4.5$

hope helpful <3

5 0

3 years ago

Read 2 more answers

Help with Pre Calculus

marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. $x(2x^2-x-15)$ . So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\$ . So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}$

4 0

2 years ago

Calculate the value of A in the statement​

Calculate the value of A in the statement