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4 years ago

11

A museum has a wax sculpture of a historical village. The scale is 1.5:8. If the height of a hut in the sculpture is 5 feet, how

tall is the original hut to the nearest whole foot?

1 answer:

Oksi-84 [34.3K]4 years ago

4 0

Let us say that x is the real height of the original hut, therefore we can establish the equation:

5 : x = 1.5 : 8

5 / x = 1.5 / 8

Solving for x:

x = 5 * 8 / 1.5

x = 40 / 1.5

<span>x = 26.67 ft</span>

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Muna has a piece of string that is 4 2/3 yards long. If she cuts it into pieces that are each 2/3 yard long, how many pieces of

bonufazy [111]

To start you would turn 4 2/3 into a mixed number by multiplying 4 and 3 and adding 2. Your mixed number would be 14/3. Then, you want to find how many 2/3 yard long pieces of string will fit into 14/3 so you devid 14/3 by 2/3 and you get 7. So 7 2/3 yard pieces of string will fit into 4 2/3.

To check your work you can multiply 2/3 by 7 and you will get 4 2/3.

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3 years ago

What is the perpendicular height of an oblique prism with a volume of 144 cubic units and an area of 24 square units

givi [52]

Answer:

Height of the oblique prism is 18 units.

Step-by-step explanation:

Volume of an oblique prism = $\frac{1}{3}(\text{Area of the base})(\text{Perpendicular height})$

Area of the base of this prism = 24 square units

And volume of the prism = 144 cubic units

By substituting these values in the formula,

144 = $\frac{1}{3}(24)(h)$

h = $\frac{144\times 3}{24}$

h = $\frac{432}{24}$

h = 18 units

Therefore, height of the oblique prism is 18 units.

4 0

4 years ago

Correct answers only please!

Zina [86]

Answer:

C. 56.2 is correct

Step-by-step explanation:

24.5x = 1378

x =56.24 mph

3 0

3 years ago

Read 2 more answers

A jar has 2 red marbles and 3 blue marbles. Two marbles are drawn at random without replacement from the jar.

ruslelena [56]

Answer: The required answers are

(a) 0.4.

(b) 0.3.

Step-by-step explanation: Given that a jar has 2 red marbles and 3 blue marbles and two marbles are drawn at random without replacement from the jar.

We are to find the probability that

(a) the second marble is red.

(b) the second marble is red, given that the first is blue.

(a) Here, we need to find the probability that the second ball drawn is red. That is, the first ball may be red or blue.

If first ball is red, then the probability that the second ball is red is given by

$p_1=\dfrac{2}{5}\times\dfrac{1}{4}=\dfrac{1}{10}.$

If first ball is blue, then the probability that the second ball is red is given by

$p_2=\dfrac{3}{5}\times\dfrac{2}{4}=\dfrac{3}{10}.$

Therefore, the probability that the second ball drawn is red is

$p=p_1+p_2=\dfrac{1}{10}+\dfrac{3}{10}=\dfrac{4}{10}=\dfrac{2}{5}=0.4.$

(b) Here, we need to find the probability that the second marble is red, given that the first is blue.

From part (a), we get that

the probability that the second ball is red, given that the first marble drawn is blue is

$p=\dfrac{3}{10}=0.3.$

Thus, the required answers are

(a) 0.4

(b) 0.3.

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4 years ago

Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).

S_A_V [24]

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-3}{2-0}\implies \cfrac{-4}{2}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=-2(x-0) \\\\\\ y-3=-2x\implies y=-2x+3$

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3 years ago