The last one, d, 2/3 < g < 2
Answer:
3c=273
c=91
2c= 212
C= 106
c= 91+ 106= 197
so they will need 197 canoes total
Why:
So first you have to determine a set variable to represent the number of canoes, I chose C. Then you make an equation to represent the number of canoes 273 people will use if they group into 3's, from this I got 3c=273. Solve for C and get 91.
The remainder of the group which is 485-273= 212 will use canoes in groups of 2's. To represent this, 2c=212. Solve for C and get 106. Combine 106 and 91 to get the total number of canoes.
Answer:
option C
c.
least: $101
greatest: $1001
Step-by-step explanation:
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.
Sum of 10 prizes = 5510
100 is the difference. there is a common difference d=100
So its a arithmetic sequence
the sum formula for arithmetic sequence is

Sn = 5510, n=10 n d= 100 we need to find out first term a1

5510 = 5 (2a1 + 900)
5510 = 10a1 + 4500
Subtract 4500 on both sides
1010= 10a1
divide by 10 on both sides
a1 = 101
so first term that is least term is 101
To find out greatest term we use formula

a(10) = 101 + (10-1)100
= 101 + 900= 1001
greatest is 1001
Answer:
The solution of the given set in interval form is
.
Step-by-step explanation:
It is given in the question an inequality as
.
It is required to determine the solution of the inequality.
To determine the solution of the inequality, solve the inequality
and, 
Step 1 of 2
Solve the inequality 

Solve the inequality
.

Step 2 of 2
The common solution from the above two solutions is x less than -4 and
.
The solution set in terms of interval is
.