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3 years ago

ACDE was translated down and right to form triangle

Mathematics

1 answer:

babymother [125]3 years ago

5 0

Answer:the correct answer is ab,ef

Step-by-step explanation:

1,2,5,6 just took test

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Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

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3 years ago

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lesantik [10]

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nignag [31]

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3 years ago

Vavilen inflated a huge balloon in 19 minutes. Then he poked a hole in the balloon so that it slowly leaked air out until it was

kaheart [24]

Considering balloon to be an spherical object

Volume of sphere = $\frac{4}{3}\pi r^3$ , where r is the radius of sphere.

After 19 minutes ,If radius of balloon changes from r to R, the Volume changes from V to V'.

V'= $\frac{4}{3}\pi R^3$ ,

As given,rate at which the air leaked out of the balloon (in liters of air per minute) was half of the rate at which Vavilen inflated the balloon.

Also, $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

Now, again the radius changes from R to r.So, Volume changes from V' to Back to V.

Time taken by the balloon to deflate = 38 minutes

But there is no relation between time and volume of Balloon.

So, we can't predict at which rate balloon is deflating or inflating.Apart from the statement given in Question: $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

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3 years ago

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